A soccer ball is kicked from the ground by the goalie and lands 40 meters from where it was kicked. The ball's path is that of a parabola, and the ball reaches a maximum height of 3 meters. Find the equation of the parabola that models this situation (assuming an axis of symmetry at x = 0). 02=-=-3 100 (-3) 400 3 (-3) 400 (x-3) 3 O(x-3)=- 400

Q: Write the equation of the parabola given by y? + 2y + 12x – 23 = 0 in standard form. %3D -

A: Given equation of parabola is y2 + 2y + 12x - 23 = 0

Q: Determine the equation of a parabola whose zeros are 2 and -11 and whose graph passes through the…

A: The zeros of the parabola are 2 and -11 and the graph passes through the point (3, 84). Let the…

Q: When constructing the standard equation of a parabola, how do you know when the p value is negative?

A: When constructing the standard equation of a parabola, how do you know when the p value is negative?

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Q: Find the equation of a parabola whose latus rectum is joined by points (2, 1) and (-4, 1)

A: Use equation of parabola

Q: 6) Write an equation of the parabola with the vertex (3, -1) and the focus (3, -5).

A: Equation of parabola is

Q: Find an equation of the parabola with vertex (-4,-5) and focus (1,-5)

A:

Q: What is the standard equation of the parabola whose vertex is at (5, -2), has a horizontal axis of…

A:

Q: a. Consider the parabola f(x) = x² -4x + 3 i) Write the equation in vertex form. ii) Find the vertex…

A: