A soccer ball is kicked at a velocity of 30 m/s at an angle of 40° with the horizontal. What is the vertical part of the velocity? v = 30 m/s 40

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**Problem:**

A soccer ball is kicked at a velocity of 30 m/s at an angle of 40° with the horizontal. What is the vertical part of the velocity?

**Diagram Explanation:**

The diagram shows a stick figure kicking a soccer ball. An arrow represents the ball's velocity vector at 30 m/s, angled 40° above the horizontal axis. The vector is broken into horizontal and vertical components, illustrating the concept of vector resolution.

**Answer Choices:**

- 23 m/s
- 19.3 m/s
- 30 m/s
- 20 m/s

The question asks for the vertical component of the velocity, which can be calculated using the formula:

\[ v_y = v \cdot \sin(\theta) \]

where \( v \) is the initial velocity (30 m/s) and \( \theta \) is the angle (40°).
Transcribed Image Text:**Problem:** A soccer ball is kicked at a velocity of 30 m/s at an angle of 40° with the horizontal. What is the vertical part of the velocity? **Diagram Explanation:** The diagram shows a stick figure kicking a soccer ball. An arrow represents the ball's velocity vector at 30 m/s, angled 40° above the horizontal axis. The vector is broken into horizontal and vertical components, illustrating the concept of vector resolution. **Answer Choices:** - 23 m/s - 19.3 m/s - 30 m/s - 20 m/s The question asks for the vertical component of the velocity, which can be calculated using the formula: \[ v_y = v \cdot \sin(\theta) \] where \( v \) is the initial velocity (30 m/s) and \( \theta \) is the angle (40°).
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