A= Só 6x (2-x²)² dx ansule=7

Q: 3 dx 25¢16x2

A: We can evaluate the given integral by using the following formula.

Q: ln(r^6s^5 5√r^8s^9) is equal to A ln r+B ln s where a=? b=?

A: lnr6s5 r8s95Concepts:ln (m n )= ln(m)+ln(n)ln am=m ln aam*an=am+namn=amn

Q: -2(x¹-x²)dx ANSWER: 42-In16

A:

Q: Solve for x x/12.4=4ft 6in/6ft 3 in

A: 1 ft=12 inch 4 ft 6 inches =4(12)+6=54 inches 6 ft 3 inches =6(12)+3=75 inches

Q: dx 4. 8 + 2r2

A: The solution of the problem is given in the next step.

Q: 2 3 ln x² dx 13mx 히 X

A: Given problem:- ∫ 3ln(x^2) dx/x

Q: How does 2sec(t/2) is equal to 1/2sec(t/2)?

A:

Q: Evaluate (2x² - 4x + 1)² dx. √

A: Given data:- ∫x32x3-4x+12dx

Q: -4 dx 2. 510

A:

Q: Find: d dx (4æ5 За? + 5х — 1) |

A:

Q: Evaluate dx. /25 – x²

A: First of all, let x = 5 sin (u) and differentiate w.r.t x on both sides of the equation and find dx.

Q: (3 In z + 2)4 dz Z

A: The given integral is (3 lnz +2)4/z.

Q: d dx 1 + 11* 3, x2

A: Given function is e5+1x23+11x

Q: Evaluate: 9 x° e- dx = 3

A: Applying product rule, ∫9x3e-xdx=9x3∫e-xdx+∫d(9x3)dx∫e-xdx dx

Q: (Зx) 2 dx x2

A: Given: ∫J23xx2dx

Q: dx 2. メ+2

A:

Q: r4 2V dx Vx 15. 1

A: The integral is given by,

Q: dx 3. 19-X

A:

Q: [e³(5e* + 8) 6 dx.

A: see below the answer and calculation

Q: In x dx Se x

A:

Q: L(cosh 4t) = %3D .a s²-16 .b O s2 – 8 .cO s²+16 S

A: option :- a

Q: x²dx a. V2x-x2 x2 dx b. 1-х6

A:

Q: e2x 9) S dx 25-e4x

A: To find the value of the given integral, first we use substitute e2x=t, then we use the integration…

Q: 1 8.) d.x (x2 + 16)3/2

A: We have to find

Q: Q3:A/ Find: 7/2 (1 + ecot) csc2 e de /4

A:

Q: 1 10. dx x² Vx² – 4 -

A:

Q: d 2r = 2 . 3x² . In 2 3. dx

A: Given, ddx2x3