A small portion (2.22 mL) of ascorbic acid solution (0.2310 mg/L) was transferred to a volumetric flask. Then, water was added up to the100.0 ml mark of the volumetric flask (ie, the final volume of the diluted solution was 100.0 mL) Calculate the concentration (in mg/L) ofthe diluted ascorbic acid solution.

We can calculate the concentration of the diluted ascorbic acid solution using the following…

Answered: A small portion (2.22 mL) of ascorbic…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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44. You have three sodium carbonate solutions on a lab table in front of you. All of the solutions came from a 500.0-mL volumetric flask containing 3.00 M sodium carbonate. Solution 1: 100.0 mL of the 3.00 M solution. Solution 2: 50.0 mL of the 3.00 M solution. Solution 3: 10.0 mL of the 3.00 M solution. What is the new concentration of Solution 2 if 14.8 g of solid sodium carbonate is added and dissolved? (Assume no volume change.) a. 11.8 M b. 0.579 M c. 5.79 M d. 2.79 M e. 1.81 M
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A student measured the mass of an empty micropicnometer to be 2.000g. A student places 0.500mL of citric acid solution into a micropicnometer. The student reweighed the micropicnometer and found the mass of the citric acid solution and micropicnometer to be 2.525g. A student titrates 0.101mL of citric acid solution using the standardized 0.1M solution (use the exact concentration calculated from the previous titration problem). The sample required 0.819mL of NaOH solution to reach the end point. Given the following chemical equation. NaOH + H3C6H5O7 → Na+ + H2O + C6H5O73- Given the above information. Calculate the mass of citric acid in the 0.101mL citric acid solution. Given the above information. Calculate the total mass of the 0.101mL citric acid solution.
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