A small metal sphere, carrying a net charge of q1 = -3.00 µC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q2 = -7.20 µC and mass 1.90 g, is projected toward q1. When the two spheres are 0.800 m apart, q2 is moving toward q1 with speed 22.0 m/s (Figure 1). Assume that the two spheres can be treated as point charges. You can ignore the force of gravity.
A small metal sphere, carrying a net charge of q1 = -3.00 µC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q2 = -7.20 µC and mass 1.90 g, is projected toward q1. When the two spheres are 0.800 m apart, q2 is moving toward q1 with speed 22.0 m/s (Figure 1). Assume that the two spheres can be treated as point charges. You can ignore the force of gravity.
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Transcribed Image Text:mv = +0.4598 J+ (0.2427 J – 0.4854 J)
= 0.2171 J
A small metal sphere, carrying a net charge of
q1 = -3.00 µC, is held in a stationary position by
insulating supports. A second small metal sphere, with a
net charge of q2 = -7.20 µC and mass 1.90 g, is
projected toward g1. When the two spheres are 0.800 m
apart, q2 is moving toward q1 with speed 22.0 m/s
(Figure 1). Assume that the two spheres can be treated
as point charges. You can ignore the force of gravity.
2(0.2171 J)
= 15.1 m/s.
kg
Vb =
1.90x10-3
EVALUATE: The potential energy increases when the two nega
and speed decrease.
Part B
How close does q2 get to q1?
Figure
1 of 1
Express your answer in meters.
HA
Value
Units
r =
v = 22.0 m/s
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0.800 m
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