A small magnet produces a deflection of 250 in Tan B position.The deflection, if a small magnet of magnetic moment 4M be placed at double distance in TanA position is 1) 50° 2) 250 3) 350 4) 530

Q: When the N end of a magnet moves towards a loop of wire from the left, the wire loop experiences an…

A: The correct option is (b) .  i.e When the N end of a magnet moves towards a loop of wire from the…

Q: b)     A long wire is bent to form 46-turns of circular loop. Each loop has an area of 3.7 cm2.…

A: Number of turns; n = 46  Area of each loop: A = 3.7 cm2 = 3.7 x10-4 m2  Magnetic field at the centre…

Q: An electron and a

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Q: what is the magnitude of the torque and magnetic potential energy acting on wire about an axis on…

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Q: A 10A current in a circular loop produces a magnetic field near the center of the loop of 0.5 Tesla.…

A: Given data The current in the circuit is given as I = 10 A. The magnetic field is given as B = 0.5…

Q: 10) Two parallel conductors carry current in opposite directions as shown below. One conductor…

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Q: A coil with magnetic moment 1.44 A m² is oriented initially with its magnetic moment antiparallel to…

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Q: A small bar magnet is suspended in a uniform 0.30 T magnetic field. The maximum torque experienced…

A: Answer is uploaded in 2nd step.

Q: The magnitude of the magnetic field at the center of a 35-turn loop of wire is 2.1 x 10-6 T.…

A: Given data: The number of turns is n=35. The magnetic field is B=2.1x10-6 The radius of loop is…

Q: A loop of current carrying wired is in a 1.6 T magnetic field. a) For the magnetic torque on the…

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Q: A rectangular loop of wire of width 10 cm and lengut 20 cn has a current of 2.5 A flowing through it…

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Q: When the N end of a magnet moves towards a loop of wire from the left, the wire loop experiences an…

A: The magnetic field lines in the bar magnetic is always from North to south pole.

Q: A wire of length 17.3 cm carrying a current of 5.94 mA is to be formed into a circular coil and…

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Q: Some pacemakers employ magneticreed switches to enable doctors to change their mode of…

A: Using Ampere's law, the expression for find current is B=μ0I2πrI=B2πrμ0

Q: 25-27. A current of 10.0 A flows through a rod of length 0.20 m placed perpendicularly across a…

A: Given Length of rod is L=0.20  m Current flowing through the rod is I=10.0  A Magnetic field is…