A small hair salon in Denver, Colorado, averages about 25 customers on weekdays with a standard deviation of 8. It is safe to assume that the underlying distribution is normal. In an attempt to increase the number of weekday customers, the manager offers a $5 discount on 6 consecutive weekdays. She reports that her strategy has worked since the sample mean of customers during this 6 weekday period jumps to 31. [You may find it useful to reference the z table.) a. What is the probability to get a sample average of 31 or more customers if the manager had not offered the discount? (Round "z" value to 2 decimal places, and final answer to 4 decimal places.) Probability b. Do you feel confident that the manager's discount strategy has worked? O No, there is good chance (more than 5%) of getting 31 or more customers without the discount. O No, there is only a small chance (less than 5%) of getting 31 or more customers without the discount. O Yes, there is good chance (more than 5%) of getting 31 or more customers without the discount. O Yes, there is only a small chance (less than 5%) of getting 31 or more customers without the discount.

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A small hair salon in Denver, Colorado, averages about 25 customers on weekdays with a standard deviation of 8. It is safe to assume
that the underlying distribution is normal. In an attempt to increase the number of weekday customers, the manager offers a $5
discount on 6 consecutive weekdays. She reports that her strategy has worked since the sample mean of customers during this 6
weekday period jumps to 31. [You may find it useful to reference the z table.]
a. What is the probability to get a sample average of 31 or more customers if the manager had not offered the discount? (Round "z"
value to 2 decimal places, and final answer to 4 decimal places.)
Probability
b. Do you feel confident that the manager's discount strategy has worked?
O No, there is good chance (more than 5%) of getting 31 or more customers without the discount.
O No, there is only a small chance (less than 5%) of getting 31 or more customers without the discount.
O Yes, there is good chance (more than 5%) of getting 31 or more customers without the discount.
O Yes, there is only a small chance (less than 5%) of getting 31 or more customers without the discount.
< Prey
3 оf 8
Next>
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R
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Transcribed Image Text:A small hair salon in Denver, Colorado, averages about 25 customers on weekdays with a standard deviation of 8. It is safe to assume that the underlying distribution is normal. In an attempt to increase the number of weekday customers, the manager offers a $5 discount on 6 consecutive weekdays. She reports that her strategy has worked since the sample mean of customers during this 6 weekday period jumps to 31. [You may find it useful to reference the z table.] a. What is the probability to get a sample average of 31 or more customers if the manager had not offered the discount? (Round "z" value to 2 decimal places, and final answer to 4 decimal places.) Probability b. Do you feel confident that the manager's discount strategy has worked? O No, there is good chance (more than 5%) of getting 31 or more customers without the discount. O No, there is only a small chance (less than 5%) of getting 31 or more customers without the discount. O Yes, there is good chance (more than 5%) of getting 31 or more customers without the discount. O Yes, there is only a small chance (less than 5%) of getting 31 or more customers without the discount. < Prey 3 оf 8 Next> nere to search (? R B N M
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