A small block with mass 0.0400 kg is moving in the xy-plane. The net force on the block is described by the potential-energy function U(x,y)=(6.00 J/m2)x2−(3.75 J/m3)y3. What are the magnitude and direction of the acceleration of the block when it is at the point (x = 0.37 m, y = 0.64 m)?

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A small block with mass 0.0400 kg is moving in the xy-plane. The net force on the block is described by the potential-energy function U(x,y)=(6.00 J/m2)x2−(3.75 J/m3)y3.
What are the magnitude and direction of the acceleration of the block when it is at the point (x = 0.37 m, y = 0.64 m)?

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Solution:

 

Given Values,

mass(m)= 0.0400 kg

potential-energy function U(x,y)=(6.00 J/m2)x2(3.75 J/m3)y3

 

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