A small blob of clay is attached to one end of a massless 20.4-cm-lon rod, as in the figure. The rod's other end is free to pivot without friction so the clay swings around in a vertical circle. What is the clay speed at point B if it is released from rest at point A with 0 = 8° and = 7°? [Note: Be careful with units!] A %0 = 0 V= Jo AU B m/s
A small blob of clay is attached to one end of a massless 20.4-cm-lon rod, as in the figure. The rod's other end is free to pivot without friction so the clay swings around in a vertical circle. What is the clay speed at point B if it is released from rest at point A with 0 = 8° and = 7°? [Note: Be careful with units!] A %0 = 0 V= Jo AU B m/s
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem Statement:**
A small blob of clay is attached to one end of a massless 20.4-cm-long rod, as shown in the figure. The rod’s other end is free to pivot without friction so the clay swings around in a vertical circle. What is the clay's speed at point \( B \) if it is released from rest at point \( A \) with \( \theta = 8^\circ \) and \( \phi = 7^\circ \)?
[Note: Be careful with units!]
---
**Diagram Explanation:**
The diagram illustrates a vertical circle with the pivot point at the top. A massless rod of 20.4 cm is shown with a blob of clay attached to its end, moving in a circular path.
- Point \( A \) is the starting position where the blob of clay is at an angle of \( \theta = 8^\circ \) from the vertical.
- The initial speed at point \( A \) is \( v_0 = 0 \).
- Point \( B \) is at an angle \( \phi = 7^\circ \) from the horizontal, on the other side of the circle.
- The problem asks for the speed \( v \) of the clay at point \( B \).
---
**Equation to Solve:**
The speed of the clay at point \( B \) (denoted as \( v \)) can be calculated using principles of energy conservation, accounting for gravitational potential energy and kinetic energy changes between points \( A \) and \( B \).
\[
v = \, \underline{\hspace{2cm}} \, \text{m/s}
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F047a7e6a-f025-4b5b-ab83-4ffe14f69253%2Fda854021-0657-4a05-b8fd-a80221bbe4bd%2Fu1lpdai_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
A small blob of clay is attached to one end of a massless 20.4-cm-long rod, as shown in the figure. The rod’s other end is free to pivot without friction so the clay swings around in a vertical circle. What is the clay's speed at point \( B \) if it is released from rest at point \( A \) with \( \theta = 8^\circ \) and \( \phi = 7^\circ \)?
[Note: Be careful with units!]
---
**Diagram Explanation:**
The diagram illustrates a vertical circle with the pivot point at the top. A massless rod of 20.4 cm is shown with a blob of clay attached to its end, moving in a circular path.
- Point \( A \) is the starting position where the blob of clay is at an angle of \( \theta = 8^\circ \) from the vertical.
- The initial speed at point \( A \) is \( v_0 = 0 \).
- Point \( B \) is at an angle \( \phi = 7^\circ \) from the horizontal, on the other side of the circle.
- The problem asks for the speed \( v \) of the clay at point \( B \).
---
**Equation to Solve:**
The speed of the clay at point \( B \) (denoted as \( v \)) can be calculated using principles of energy conservation, accounting for gravitational potential energy and kinetic energy changes between points \( A \) and \( B \).
\[
v = \, \underline{\hspace{2cm}} \, \text{m/s}
\]
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