A slot machine has 3 dials. Each dial has 30 positions, one of which is "Jackpot". To win the jackpot, all three dials must be in the "Jackpot" position. Assuming each play spins the dials and stops each independently and randomly, what are the odds of one play winning the jackpot? a) 1/30 = 0.03 or 3% b) 3/(30+30+30) = 3/90 = 0.33 or 33% c) 3/(30*30*30) = 3/27000 = 0.0001 or 0.01% d) 1/(30*30*30) = 1/27000 = 0.00003 or 0.003%
A slot machine has 3 dials. Each dial has 30 positions, one of which is "Jackpot". To win the jackpot, all three dials must be in the "Jackpot" position. Assuming each play spins the dials and stops each independently and randomly, what are the odds of one play winning the jackpot? a) 1/30 = 0.03 or 3% b) 3/(30+30+30) = 3/90 = 0.33 or 33% c) 3/(30*30*30) = 3/27000 = 0.0001 or 0.01% d) 1/(30*30*30) = 1/27000 = 0.00003 or 0.003%
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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A slot machine has 3 dials. Each dial has 30 positions, one of which is "Jackpot". To win the jackpot, all three dials must be in the "Jackpot" position. Assuming each play spins the dials and stops each independently and randomly, what are the odds of one play winning the jackpot?
a) 1/30 = 0.03 or 3%
b) 3/(30+30+30) = 3/90 = 0.33 or 33%
c) 3/(30*30*30) = 3/27000 = 0.0001 or 0.01%
d) 1/(30*30*30) = 1/27000 = 0.00003 or 0.003%
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