format in solving:1. given2. diagram (simple labeled sketch)3. solution* formula (from formula sheet)* algebra* substitution* solve4. therefore statement (full answer with correct sig figs) A skier leaves the end of a ramp with a velocity of 25.0 m/s 30.0° above the horizontaloff a 95.0 m high ramp. How far down the slope will the skier land? FORMULA SHEETMotion Equations:Gravitational, Electric and Magnetic Fields:dVave =Vavg =dr = d, + d2 + d3 + ……ü = v, + ätGMmF =GMmE, =-d, = d, + dz + dz+.F, == kai =+ ü)td = ö,t +d = öt -ü2 = v,? + 2ädkogE =ΔΕAV =V = kqAE, =-AEv²a. =q = Ne= BIT sin 0F = Bqü sin 0HNIRelative Motion:B = ANIForces:Modern PhysicsEnet = må= mỹF, = µFNFnet = F, + F2 + F,+...AtoAt =L = L. 1m =Energy and Momentum:E = mc? – m.c?E =- moc²p = müAp = F At= mAip = p'Constants:т — т,g = 9.8 m/s² [Down]k = 9.0 × 10° N - m² /C?e =1.60 x 10-19CH. = 47x10"T - m/ Ac = 3.0 x 10* m / sv,'= v,|т, +т,= AmüElasticCollisionsG = 6.67 x 10-11 N-m²/kg²2m,v,'= v,m, + m,M, = 5.98×10ª kgEarthr = 6.37×10ʻmm, =1.67×10" kgm¸ = 9.11×10~" kg }Atomr, = 5.29×10"mE, -mE. = kx?W = F. Ad cos0AE¸ = mgAh

Name: format in solving:1. given2. diagram (simple labeled sketch)3. solutio
Uploaded: 2024-03-20T06:57:47.000Z
Channel: Bartleby
Description: format in solving:1. given2. diagram (simple labeled sketch)3. solution* formula (from formula sheet)* algebra* substitution* solve4. therefore statement (full answer with correct sig figs) A skier leaves the end of a ramp with a velocity of 25.0 m/s