A site is to be developed for construction of a one-story steel structure. The site is underlain by 20 ft of soft clay (GWT at ground surface), which in turn is underlain by impervious rock Five feet of freely draining fill is to be placed on the site to raise the ground surface. The structure is relatively flexible and can withstand several inches of differential settlement. It is decided early in the design phase that the maximum allowable total settlement is 2 inches. The fill has a total unit weight of 120 pcf. The soft clay is normally consolidated with the following properties (= 100 pcf, S = 100%, Gs=2.7, Cc = 0.78, C₂=0.09). Assume that the water table stays at the interface between the clay and fill during consolidation and assume that the weight of the building is negligible compared to the weight of the fill. (a) Compute the total settlement of the soft clay caused by placement of the 5 ft of fill. Use one clay layer in your calculation. (b) Calculate the time required until only 2 inches of consolidation settlement remains. The coefficient of consolidation for the clay (c) is 0.35 f/day. Assume that the clay layer is free draining only at its top. 58 20 Draining Fill Clay Layer 3-130 g 7 Point of Interest 10 71-100 pdf Impervious Rock Fig. 2 Soil Profile in Question 4

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Chapter2: Loads On Structures
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a
A site is to be developed for construction of a one-story steel structure. The
site is underlain by 20 ft of soft clay (GWT at ground surface), which in turn is underlain
by impervious rock. Five feet of freely draining fill is to be placed on the site to raise the
ground surface. The structure is relatively flexible and can withstand several inches of
differential settlement. It is decided early in the design phase that the maximum allowable
total settlement is 2 inches. The fill has a total unit weight of 120 pcf. The soft clay is
normally consolidated with the following properties (= 100 pcf, S = 100%, Gs = 2.7, Cc
= 0.78, C₂=0.09). Assume that the water table stays at the interface between the clay and
fill during consolidation and assume that the weight of the building is negligible compared
to the weight of the fill.
(a) Compute the total settlement of the soft clay caused by placement of the 5 ft of fill. Use
one clay layer in your calculation.
(b) Calculate the time required until only 2 inches of consolidation settlement remains. The
coefficient of consolidation for the clay (c) is 0.35 fi²/day. Assume that the clay layer is
free draining only at its top.
58
20
Before the fill is constructed:
Draining Fill
After the fill is constructed:
Clay Layer
1+w
1+ ²/2.7
Y?"1+? ???"T+?
→? - 1.82
%-120
Point of Interest 10
7-100 pdf
Impervious Rock
Fig. 2 Soil Profile in Question 4
? ? ?? w
⇒W
- 2.7
-*2.7 x 62.4 = 100
=y'h (100-62.4) × 10-376
10
Transcribed Image Text:a A site is to be developed for construction of a one-story steel structure. The site is underlain by 20 ft of soft clay (GWT at ground surface), which in turn is underlain by impervious rock. Five feet of freely draining fill is to be placed on the site to raise the ground surface. The structure is relatively flexible and can withstand several inches of differential settlement. It is decided early in the design phase that the maximum allowable total settlement is 2 inches. The fill has a total unit weight of 120 pcf. The soft clay is normally consolidated with the following properties (= 100 pcf, S = 100%, Gs = 2.7, Cc = 0.78, C₂=0.09). Assume that the water table stays at the interface between the clay and fill during consolidation and assume that the weight of the building is negligible compared to the weight of the fill. (a) Compute the total settlement of the soft clay caused by placement of the 5 ft of fill. Use one clay layer in your calculation. (b) Calculate the time required until only 2 inches of consolidation settlement remains. The coefficient of consolidation for the clay (c) is 0.35 fi²/day. Assume that the clay layer is free draining only at its top. 58 20 Before the fill is constructed: Draining Fill After the fill is constructed: Clay Layer 1+w 1+ ²/2.7 Y?"1+? ???"T+? →? - 1.82 %-120 Point of Interest 10 7-100 pdf Impervious Rock Fig. 2 Soil Profile in Question 4 ? ? ?? w ⇒W - 2.7 -*2.7 x 62.4 = 100 =y'h (100-62.4) × 10-376 10
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