A sinusoidal voltage Δv = 45.0 sin(100t), where Δv is in volts and t is in seconds, is applied to a series RLC circuit with L = 170 mH, C = 99.0 µF, and R = 60.0 Ω. e) What If? For what value of the inductance (in H) in the circuit would the current lag the voltage by the same angle ? as that found in part (d)?

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A sinusoidal voltage Δv = 45.0 sin(100t), where Δv is in volts and t is in seconds, is applied to a series RLC circuit with L = 170 mH, C = 99.0 µF, and R = 60.0 Ω.

e) What If? For what value of the inductance (in H) in the circuit would the current lag the voltage by the same angle ? as that found in part (d)?

A sinusoidal voltage Av = 45.0 sin(100t), where Av is in volts and t is in seconds, is applied to a series RLC circuit with L = 170 mH, C = 99.0 µF, and R = 60.0 Q.
(a) What is the impedance (in 2) of the circuit?
103.236
Ω
(b) What is the maximum current (in A)?
0.4359
A
(c) Determine the numerical value for w (in rad/s) in the equation i = Imay
sin(@t – 4).
100
rad/s
(d) Determine the numerical value for p (in rad) in the equation i = Imay sin(wt - 4).
-0.95
rad
(e) What If? For what value of the inductance (in H) in the circuit would the current lag the voltage by the same angle o as that found in part (d)?
181.9
H
(f) What would be the maximum current (in A) in the circuit in this case?
0.4359
A
Transcribed Image Text:A sinusoidal voltage Av = 45.0 sin(100t), where Av is in volts and t is in seconds, is applied to a series RLC circuit with L = 170 mH, C = 99.0 µF, and R = 60.0 Q. (a) What is the impedance (in 2) of the circuit? 103.236 Ω (b) What is the maximum current (in A)? 0.4359 A (c) Determine the numerical value for w (in rad/s) in the equation i = Imay sin(@t – 4). 100 rad/s (d) Determine the numerical value for p (in rad) in the equation i = Imay sin(wt - 4). -0.95 rad (e) What If? For what value of the inductance (in H) in the circuit would the current lag the voltage by the same angle o as that found in part (d)? 181.9 H (f) What would be the maximum current (in A) in the circuit in this case? 0.4359 A
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