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A sinusoidal voltage source of v(t) = 100cos (2π60t) V is applied to a load, resulting in a non-sinusoidal current which is expressed in Fourier series as i(t) = 15cos (2π60t +35°) + 6cos(4π60t +15°) + 1cos (860t - 10°) A The average power absorbed by the load is P = 614.364 W (b) Determine the power factor of the load. Note that P = Vrms Irmscos (0) Determine the total harmonic distortion of the load current.

A sinusoidal voltage source of v(t) = 100cos (2π60t) V is applied to a load, resulting in a non-sinusoidal current which is expressed in Fourier series as i(t) = 15cos (2π60t +35°) + 6cos(4π60t +15°) + 1cos (860t - 10°) A The average power absorbed by the load is P = 614.364 W (b) Determine the power factor of the load. Note that P = Vrms Irmscos (0) Determine the total harmonic distortion of the load current.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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A sinusoidal voltage source of v(t) = 100cos (2π60t) V is applied to a load, resulting in a non-sinusoidal current which is expressed in Fourier series as i(t) = 15cos (2π60t +35°) + 6cos(4π60t +15°) + 1cos (860t - 10°) A The average power absorbed by the load is P = 614.364 W (b) Determine the power factor of the load. Note that P = Vrms Irmscos (0) Determine the total harmonic distortion of the load current.
Transcribed Image Text:A sinusoidal voltage source of v(t) = 100cos (2π60t) V is applied to a load, resulting in a non-sinusoidal current which is expressed in Fourier series as i(t) = 15cos (2π60t +35°) + 6cos(4π60t +15°) + 1cos (860t - 10°) A The average power absorbed by the load is P = 614.364 W (b) Determine the power factor of the load. Note that P = Vrms Irmscos (0) Determine the total harmonic distortion of the load current.
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