A single resistor has a resistance of 5.0 Q and uses 25 V of potential difference (or voltage). What is the current flowing through the resistor? Your answer: 0.20 A O 5.0 A O 30 A 125 A
A single resistor has a resistance of 5.0 Q and uses 25 V of potential difference (or voltage). What is the current flowing through the resistor? Your answer: 0.20 A O 5.0 A O 30 A 125 A
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Question:
A single resistor has a resistance of 5.0 Ω and uses 25 V of potential difference (or voltage). What is the current flowing through the resistor?
### Your answer options:
- ⃝ 0.20 A
- ⃝ 5.0 A
- ⃝ 30 A
- ⃝ 125 A
### Explanation:
To determine the current flowing through the resistor, you can use Ohm's Law, which is stated as:
\[ V = I \times R \]
Where:
- \( V \) is the voltage (potential difference in volts, V)
- \( I \) is the current (in amperes, A)
- \( R \) is the resistance (in ohms, Ω)
Rearrange the formula to solve for the current \( I \):
\[ I = \frac{V}{R} \]
Given:
\[ V = 25 \, \text{V} \]
\[ R = 5.0 \, \text{Ω} \]
Substitute the given values into the formula:
\[ I = \frac{25}{5.0} = 5 \, \text{A} \]
Therefore, the current flowing through the resistor is:
- ⃝ 0.20 A
- ⃝ **5.0 A**
- ⃝ 30 A
- ⃝ 125 A](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F856a2e92-f5e0-46b6-bdd4-d30240b807e8%2Fe393d768-4509-4714-9f06-681ff419ba04%2Fhhwuei_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Question:
A single resistor has a resistance of 5.0 Ω and uses 25 V of potential difference (or voltage). What is the current flowing through the resistor?
### Your answer options:
- ⃝ 0.20 A
- ⃝ 5.0 A
- ⃝ 30 A
- ⃝ 125 A
### Explanation:
To determine the current flowing through the resistor, you can use Ohm's Law, which is stated as:
\[ V = I \times R \]
Where:
- \( V \) is the voltage (potential difference in volts, V)
- \( I \) is the current (in amperes, A)
- \( R \) is the resistance (in ohms, Ω)
Rearrange the formula to solve for the current \( I \):
\[ I = \frac{V}{R} \]
Given:
\[ V = 25 \, \text{V} \]
\[ R = 5.0 \, \text{Ω} \]
Substitute the given values into the formula:
\[ I = \frac{25}{5.0} = 5 \, \text{A} \]
Therefore, the current flowing through the resistor is:
- ⃝ 0.20 A
- ⃝ **5.0 A**
- ⃝ 30 A
- ⃝ 125 A
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