A single line diagram of a power system is shown in Fig.3.1. All the sequence reactances of the power system components are depicted in per unit on 20 MVA base, 110KV (L-L) in transmission circuit. If a single line to ground fault occurs on phase a through a reactance of 150 ohm at F, determine the current in ampere fed into the fault. The fault point F is assumed to be at 65% of transmission line length from the bus bar connected to generators A and B. 20 MVA A Xe-Xpj 0.1 X-j 0.35 11 KV C X-j0.3 X=j0.3 X=j0.05/ 110 KV 20 MVA X-X,-X-J 0.1 X=X,=X;=j 0.1 Transmission circuit X,=j0.25 X;=j0.25 X-j0.05 Y D |Xx=X;= j 0.1 X;~j 0.35 X-X-X;-J 0.1 X-X;=X;=j 0.1

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Please solve step by step subject power system analysis
A single line diagram of a power system is shown in Fig.3.1. All the
sequence reactances of the power system components are depicted in per
unit on 20 MVA base, 110KV (L-L) in transmission circuit. If a single line
to ground fault occurs on phase a through a reactance of 150 ohm at F,
determine the current in ampere fed into the fault. The fault point F is
assumed to be at 65% of transmission line length from the bus bar
connected to generators A and B.
20 MVA
X-X-j 0.1 X-j 0.35
ntn 11 KV
A
X,-j0.3
X=j0.3
X=j0.05
C
110 KV
20 MVA
X-X-X;-J 0.1
X=X=X=j 0.1
X=j0.25
Xx=j0.25
Xo=j0.05
Transmission
circuit
CY
Y
B
D
|X=Xy=j 0.1 X;-j 0.35
X-X,-X3-J 0.1
X-X,=X;=j 0.1
Transcribed Image Text:A single line diagram of a power system is shown in Fig.3.1. All the sequence reactances of the power system components are depicted in per unit on 20 MVA base, 110KV (L-L) in transmission circuit. If a single line to ground fault occurs on phase a through a reactance of 150 ohm at F, determine the current in ampere fed into the fault. The fault point F is assumed to be at 65% of transmission line length from the bus bar connected to generators A and B. 20 MVA X-X-j 0.1 X-j 0.35 ntn 11 KV A X,-j0.3 X=j0.3 X=j0.05 C 110 KV 20 MVA X-X-X;-J 0.1 X=X=X=j 0.1 X=j0.25 Xx=j0.25 Xo=j0.05 Transmission circuit CY Y B D |X=Xy=j 0.1 X;-j 0.35 X-X,-X3-J 0.1 X-X,=X;=j 0.1
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