A single bacterium divides every 0.5 hour to produce two complete bacteria. If we start with a colony of 6000 bacteria, after t hours there will be A(t) = 6000 • 2²t = 6000 4¹ bacteria. Find A'(5). A. 8,517,393 bacteria B. 34,069,570 bacteria C. 2,129,348 bacteria OD. 133,084 bacteria
A single bacterium divides every 0.5 hour to produce two complete bacteria. If we start with a colony of 6000 bacteria, after t hours there will be A(t) = 6000 • 2²t = 6000 4¹ bacteria. Find A'(5). A. 8,517,393 bacteria B. 34,069,570 bacteria C. 2,129,348 bacteria OD. 133,084 bacteria
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![A single bacterium divides every 0.5 hour to produce two complete bacteria. If we start with a colony of 6000 bacteria, after \( t \) hours there will be
\[ A(t) = 6000 \cdot 2^{2t} = 6000 \cdot 4^t \]
bacteria. Find \( A'(5) \).
Options:
- A. 8,517,393 bacteria
- B. 34,069,570 bacteria
- C. 2,129,348 bacteria
- D. 133,084 bacteria](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff2bfa172-bfc6-4a2e-9589-90b7bd2d30c6%2F9f9a1144-5763-42db-a5bd-98c7642f09b7%2Fsnm1tjn_processed.png&w=3840&q=75)
Transcribed Image Text:A single bacterium divides every 0.5 hour to produce two complete bacteria. If we start with a colony of 6000 bacteria, after \( t \) hours there will be
\[ A(t) = 6000 \cdot 2^{2t} = 6000 \cdot 4^t \]
bacteria. Find \( A'(5) \).
Options:
- A. 8,517,393 bacteria
- B. 34,069,570 bacteria
- C. 2,129,348 bacteria
- D. 133,084 bacteria
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