A simple random sample of 56 students who picked up all tests they completed was selected, and the mean score on final exam for this sample of students was 83 with astandard deviation of 10.4. An independent simple random sample of 51 students who had one or more tests that were not picked up was selected, and the mean scoreon the final exam for this sample of students was 67 with a standard deviation of 24.2. Both distributions are skewed heavily to the left [note: this is the same informationprovided in question above]. If appropriate, use this information to calculate and interpret a 99% confidence interval for the difference in the mean score on the finalexam for all students who picked up all their tests and the mean score on the final exam for all students who had one or more tests that were not picked up.17Yes, because both samples are larger than 40 and there are 2 simple random samplesYes, because any sample size will work and there are 2 simple random samplesYes, because only sample sizes of 15 are needed and there are 2 simple random samples,What are the confidence interval values using 99% confidence?(11.615, 26.385)(6.2876, 25.712)(13.506, 20.494)O(6.568, 25.434)(6.6985, 25.302)-D

Confidence interval is used to determine the parameter range where it lies. It explains true mean…

Answered: A simple random sample of 56 students…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Would it be skewed right since all the data would lie on the left side
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