A simple pendulum performs simple harmonic motion about x = 0 with an amplitude a and time period T. The speed of the pendulum at x = a/2 will be ___________ a) (πa√3)/T b) (πa√3)/2T c) πa/T d) (3π2 a)/T
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A simple pendulum performs
a) (πa√3)/T
b) (πa√3)/2T
c) πa/T
d) (3π2 a)/T
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- A simple pendulum is swinging back & forth through a small angle, its motion repeating every 1.31 s. How much longer should the pendulum be made in order to increase its period by 0.26s ?A particle executes simple harmonic motion with an amplitude of 5.00 cm. At what positions does its speed equal one third of its maximum speed? larger number cm smaller number cmLet the spring have a mass of 191.3 +/- 01g. A 75+/- 01 g mass is attached to the spring. The mass is displaced 1/2 inch and released from rest. After fitting the position data with a sine fit, the position amplitude is found to be 0.0146+/- 0.0003 M. A) calculate the angular frequency of the mass (with uncertainty) b) Determine the amplitude of the velocity of the mass (with uncertainty) c) Find the amplitude of the acceleration (with uncertainty)
- For a simple pendulum, the restoring "force" is the torque due to gravity, mgL. Here m is the mass of the pendulum, g is the acceleration due to gravity, and L is the length of the pendulum. The "inertia" is the rotational inertia, mL². What is the expected period T of a simple pendulum? OA. 2л√/mg/L OB. 2√✓/L/mg OC. 2n√L/g OD. 2n√g/L OE. none of theseA particle executes simple harmonic motion with an amplitude of 9.00 cm. At what positions does its speed equal one-half of its maximum speed? larger number cm smaller number cmtion - A pendulum 4.03 m in length swings through 47 degrees. Calculate the curvilinear distance (s) traveled by its tip to 2 decimal places. Answer: pe here to search E D da. D R F Bi T G 6 B Y & H N U J 8 1 M N 9 K S Ps L >> P Next page ASXXCTD +1.33% Fint