A simple pendulum of length L, has amaximum angular displacemente_max. At one point in its motion, itskinetic energy is K = 3 J and itspotential energy is U = 4.2 J. Whenthe pendulum's angular velocity isone-fourth its maximum value (0' =%3DO'_max/4), then its kinetic energy is:

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Answered: A simple pendulum of length L, has a…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Consider a system of linear equations in the form of BX = A, where x is the unknown vector. Which of the following can be used to solve for x? -_-_-_-_-_-_-_-_-_-_-_-_-_-_- .….….….…..……….….….….…..….….…..…….….…….….….…... Select one: O a. X = inv(B)./A b. X = BIAOXO DXD OXO OXO OXO OHO C. X =A\B Brid ○ d. X = B./A 0²% 0²% 0²% 0²% 0²:0²: e. X = inv(A)*B
This is discrete math:
2. calculates the trajectory r(t) and stores the coordinates for time steps At as a nested list trajectory that contains [[xe, ye, ze], [x1, y1, z1], [x2, y2, z2], ...]. Start from time t = 0 and use a time step At = 0.01; the last data point in the trajectory should be the time when the oscillator "hits the ground", i.e., when z(t) ≤ 0; 3. stores the time for hitting the ground (i.e., the first time t when z(t) ≤ 0) in the variable t_contact and the corresponding positions in the variables x_contact, y_contact, and z_contact. Print t_contact = 1.430 X_contact = 0.755 y contact = -0.380 z_contact = (Output floating point numbers with 3 decimals using format (), e.g., "t_contact = {:.3f}" .format(t_contact).) The partial example output above is for ze = 10. 4. calculates the average x- and y-coordinates 1 y = Yi N where the x, y, are the x(t), y(t) in the trajectory and N is the number of data points that you calculated. Store the result as a list in the variable center = [x_avg, y_avg]…
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A simple pendulum of length L, has a maximum angular displacement e_max. At one point in its motion, its kinetic energy is K = 3 J and its %3D potential energy is U = 4.2 J. When the pendulum's angular velocity is one-fourth its maximum value (e' = e'_max/4), then its kinetic energy is: