A simple pendulum is set into motion at two different times with different initial conditions. The first time: the bob is in its equilibrium position and is given an initial velocity + 2 m/s. The maximum height reached by the bob is h1,max and the period of motion is T1. The second time: the bob is in its equilibrium position and is given an initial velocity + 4 m/s. The maximum height reached by the bob is h2,max and the period of motion is T2. Assume that the motion is simple harmonic, which of the following is true?

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A simple pendulum is set into motion at two different times with different initial
conditions. The first time: the bob is in its equilibrium position and is given an
initial velocity + 2 m/s. The maximum height reached by the bob is h1,max and the
period of motion is T1. The second time: the bob is in its equilibrium position and
is given an initial velocity + 4 m/s. The maximum height reached by the bob is
h2,max and the period of motion is T2. Assume that the motion is simple
harmonic, which of the following is true?
and T, = 37
h2max = 4h1,max and T2 = T,
9h1max
2,max
Transcribed Image Text:A simple pendulum is set into motion at two different times with different initial conditions. The first time: the bob is in its equilibrium position and is given an initial velocity + 2 m/s. The maximum height reached by the bob is h1,max and the period of motion is T1. The second time: the bob is in its equilibrium position and is given an initial velocity + 4 m/s. The maximum height reached by the bob is h2,max and the period of motion is T2. Assume that the motion is simple harmonic, which of the following is true? and T, = 37 h2max = 4h1,max and T2 = T, 9h1max 2,max
Then we have :
O Then we have:
h2.max
4h, max and T, = 27,
h2.max = h1,max/2 and T2 = T1
%3D
%3|
O Then we have:
Then we have:
h2max = 9hmax and T, = T,
%3D
Then we have:
Transcribed Image Text:Then we have : O Then we have: h2.max 4h, max and T, = 27, h2.max = h1,max/2 and T2 = T1 %3D %3| O Then we have: Then we have: h2max = 9hmax and T, = T, %3D Then we have:
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