A simple pendulum is set into motion at two different times with different initial conditions. The first time: the bob is in its equilibrium position and is given an initial velocity +4 m/s. The maximum height reached by the bob is h1,max and the period of motion is T1. The second time: the bob is in its equilibrium position and is given an initial velocity +2 m/s. The maximum height reached by the bob is h2,max and the period of motion is T2. Assume that the motion is simple harmonic, which of the following is true? h2max = 9hmax and T2 = 37, h2.max = h1,max/4 and T2 = T1 Then we have: Then we have: h2.max = 9h,max and T2 = T, h2max = 4hmax and T2 = 2T, Then we have: O Then we have: h2max=4h,max and T2 T, O Then we have:
A simple pendulum is set into motion at two different times with different initial conditions. The first time: the bob is in its equilibrium position and is given an initial velocity +4 m/s. The maximum height reached by the bob is h1,max and the period of motion is T1. The second time: the bob is in its equilibrium position and is given an initial velocity +2 m/s. The maximum height reached by the bob is h2,max and the period of motion is T2. Assume that the motion is simple harmonic, which of the following is true? h2max = 9hmax and T2 = 37, h2.max = h1,max/4 and T2 = T1 Then we have: Then we have: h2.max = 9h,max and T2 = T, h2max = 4hmax and T2 = 2T, Then we have: O Then we have: h2max=4h,max and T2 T, O Then we have:
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![A simple pendulum is set into motion at two different times with different initial
conditions. The first time: the bob is in its equilibrium position and is given an
initial velocity +4 m/s. The maximum height reached by the bob is h1,max and the
period of motion is T1. The second time: the bob is in its equilibrium position and
is given an initial velocity +2 m/s. The maximum height reached by the bob is
h2,max and the period of motion is T2. Assume that the motion is simple
harmonic, which of the following is true?
h2 max = 9h,max and T2 3T,
h2.max = h1max/4 and T2 T,
Then we have:
Then we have:
h2max
= 9h, max and T = T,
h2.max = 4h,max and T2 = 2T,
Then we have:
O Then we have:
h2max = 4hmax and T2 T,
O Then we have:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1ef5a582-ecba-4e4f-8d27-c699a147ed31%2Fcba011ae-9189-4eb8-b0e2-afb09e3b8166%2Ftibhvp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A simple pendulum is set into motion at two different times with different initial
conditions. The first time: the bob is in its equilibrium position and is given an
initial velocity +4 m/s. The maximum height reached by the bob is h1,max and the
period of motion is T1. The second time: the bob is in its equilibrium position and
is given an initial velocity +2 m/s. The maximum height reached by the bob is
h2,max and the period of motion is T2. Assume that the motion is simple
harmonic, which of the following is true?
h2 max = 9h,max and T2 3T,
h2.max = h1max/4 and T2 T,
Then we have:
Then we have:
h2max
= 9h, max and T = T,
h2.max = 4h,max and T2 = 2T,
Then we have:
O Then we have:
h2max = 4hmax and T2 T,
O Then we have:
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