A simple pendulum is set into motion at two different times with different initial conditions. The first time: the bob is in its equilibrium position and is given an initial velocity +2 m/s. The maximum height reached by the bob is h1,max and the period of motion is T1. The second time: the bob is in its equilibrium position and is given an initial velocity +6 m/s. The maximum height reached by the bob is h2,max and the period of motion is T2. Assume that the motion is simple harmonic, which of the following is true?

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A simple pendulum is set into motion at two different times with different initial
conditions. The first time: the bob is in its equilibrium position and is given an
initial velocity +2 m/s. The maximum height reached by the bob is h1,max and the
period of motion is T1. The second time: the bob is in its equilibrium position and
is given an initial velocity +6 m/s. The maximum height reached by the bob is
h2,max and the period of motion is T2. Assume that the motion is simple
harmonic, which of the following is true?
h2.max = 9hmax and T2 = T
%3D
h2.max = h.max/2 and T2 = T,
%3D
Then we have:
Then we have:
h2,max
= 4h1 max and T = T,
hmay = 4hmax and T, = 27,
Transcribed Image Text:A simple pendulum is set into motion at two different times with different initial conditions. The first time: the bob is in its equilibrium position and is given an initial velocity +2 m/s. The maximum height reached by the bob is h1,max and the period of motion is T1. The second time: the bob is in its equilibrium position and is given an initial velocity +6 m/s. The maximum height reached by the bob is h2,max and the period of motion is T2. Assume that the motion is simple harmonic, which of the following is true? h2.max = 9hmax and T2 = T %3D h2.max = h.max/2 and T2 = T, %3D Then we have: Then we have: h2,max = 4h1 max and T = T, hmay = 4hmax and T, = 27,
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