Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
A simple pendulum is formed of a bob of mass m attached to a string of length L. The bob is displaced from its equilibrium position by an angle 0 = +8.6° and then released from rest. At the bottom of its path (at 0 = 0), the bob has a speed of 0.8 m/s. The bob will reach -e max for the first time after: (g = 9.8 m/s^2) %3D O at = 1.496 s O At = 1.282 s O at = 0.855 s O at = 1.709 s Oat 0.214 s Oat 0.641 s

A simple pendulum is formed of a bob of mass m attached to a string of length L. The bob is displaced from its equilibrium position by an angle 0 = +8.6° and then released from rest. At the bottom of its path (at 0 = 0), the bob has a speed of 0.8 m/s. The bob will reach -e max for the first time after: (g = 9.8 m/s^2) %3D O at = 1.496 s O At = 1.282 s O at = 0.855 s O at = 1.709 s Oat 0.214 s Oat 0.641 s

icon
Related questions
Question
A simple pendulum is formed of a bob of mass m attached to a string of length L. The bob is displaced from its equilibrium position by an angle 0 = +8.6° and then released from rest. At the bottom of its path (at 0 0), the bob has a speed of 0.8 m/s. The bob will reach -e max for the first time after: (g = 9.8 m/s^2) O at = 1.496 s O at = 1.282 s O at = 0.855 s O at = 1.709 s O At = 0.214 s O At = 0.641 s
Transcribed Image Text:A simple pendulum is formed of a bob of mass m attached to a string of length L. The bob is displaced from its equilibrium position by an angle 0 = +8.6° and then released from rest. At the bottom of its path (at 0 0), the bob has a speed of 0.8 m/s. The bob will reach -e max for the first time after: (g = 9.8 m/s^2) O at = 1.496 s O at = 1.282 s O at = 0.855 s O at = 1.709 s O At = 0.214 s O At = 0.641 s
Expert Solution
steps

Step by step

Solved in 3 steps with 3 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer