### Understanding Ohmmeter Construction#### Problem OverviewA simple ohmmeter is constructed by connecting a 2.50 V battery in series with a resistance \( R \) and an ammeter. The ammeter has a range of 0 to 1.00 mA. When the clip leads are shorted together, the meter deflects to its full-scale value of 1.00 mA. Your task is to determine the external resistance that results in particular deflections, and also to find the value of \( R \).#### Questions to Solve1. What external resistance across the leads results in a deflection of: - \( a) \) 9.00% - \( b) \) 54.9% - \( c) \) 85.7% of full scale?2. Given the ammeter has a resistance of 15.6 \( \Omega \) and the internal resistance of the battery is negligible, what is the value of \( R \)?#### Circuit DiagramThe figure shown depicts the setup of the circuit:- **Battery**: 2.50V- **Ammeter**: Reads 0 to 1.00 mA- **Resistance \( R \)**: To be adjusted- **External Resistance across leads**: To determine the values for given deflectionsThe circuit diagram can be described as follows:- The positive terminal of the 2.50 V battery is connected to the ammeter.- The ammeter is connected in series to the resistance \( R \).- The resistance \( R \) is then connected back to the negative terminal of the battery.- Two clip leads extend from the connections between the ammeter and \( R \), with a space indicated for attaching an external resistance.#### Diagram ExplanationIn the circuit diagram:- The battery supplies a constant voltage of 2.50V.- The ammeter measures the current flowing through the circuit.- When the clip leads are shorted (no external resistance), the meter reads the full-scale current of 1.00 mA.- Adjusting the resistance \( R \) impacts the current read by the ammeter.### Detailed Steps for Solution1. **Shorted Leads:** - Voltage, \( V = 2.50 \text{ V} \) - Current, \( I = 1.00 \text{ mA}

Answered: Image /qna-images/answer/738845fb-71c9-485d-8ede-762f72f0e31d.jpg

A simple ohmmeter is made by connecting a 2.50 V battery in series with a resistance R and an ammeter that reads from 0 to 1.00 mA, as shown in the figure. Resistance R is adjusted so that when the clip leads are shorted together, the meter deflects to its full-scale value of 1.00 mA. What external resistance across the leads results in a deflection of (a) 9.00%, (b) 54.9%, and (c)85.7% of full scale? (d) If the ammeter has a resistance of 15.6 Q and the internal resistance of the battery is negligible, what is the value of R? Ef 0-1.00) mA R

A simple ohmmeter is made by connecting a 2.50 V battery in series with a resistance R and an ammeter that reads from 0 to 1.00 mA, as shown in the figure. Resistance R is adjusted so that when the clip leads are shorted together, the meter deflects to its full-scale value of 1.00 mA. What external resistance across the leads results in a deflection of (a) 9.00%, (b) 54.9%, and (c)85.7% of full scale? (d) If the ammeter has a resistance of 15.6 Q and the internal resistance of the battery is negligible, what is the value of R? Ef 0-1.00) mA R

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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### Understanding Ohmmeter Construction

#### Problem Overview
A simple ohmmeter is constructed by connecting a 2.50 V battery in series with a resistance \( R \) and an ammeter. The ammeter has a range of 0 to 1.00 mA. When the clip leads are shorted together, the meter deflects to its full-scale value of 1.00 mA. Your task is to determine the external resistance that results in particular deflections, and also to find the value of \( R \).

#### Questions to Solve
1. What external resistance across the leads results in a deflection of:
- \( a) \) 9.00%
- \( b) \) 54.9%
- \( c) \) 85.7% of full scale?

2. Given the ammeter has a resistance of 15.6 \( \Omega \) and the internal resistance of the battery is negligible, what is the value of \( R \)?

#### Circuit Diagram
The figure shown depicts the setup of the circuit:
- **Battery**: 2.50V
- **Ammeter**: Reads 0 to 1.00 mA
- **Resistance \( R \)**: To be adjusted
- **External Resistance across leads**: To determine the values for given deflections

The circuit diagram can be described as follows:
- The positive terminal of the 2.50 V battery is connected to the ammeter.
- The ammeter is connected in series to the resistance \( R \).
- The resistance \( R \) is then connected back to the negative terminal of the battery.
- Two clip leads extend from the connections between the ammeter and \( R \), with a space indicated for attaching an external resistance.

#### Diagram Explanation
In the circuit diagram:
- The battery supplies a constant voltage of 2.50V.
- The ammeter measures the current flowing through the circuit.
- When the clip leads are shorted (no external resistance), the meter reads the full-scale current of 1.00 mA.
- Adjusting the resistance \( R \) impacts the current read by the ammeter.

### Detailed Steps for Solution
1. **Shorted Leads:**
- Voltage, \( V = 2.50 \text{ V} \)
- Current, \( I = 1.00 \text{ mA}

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