A simple curve has a central angle of 38° and a degree of curve of 6". a.) Find the nearest distance from the midpoint of the curve to the point of intersection of the tangents. a. 10.27 m b. 9.83 m c. 8.47 m d. 7.27 m b.) Compute the distance from the midpoint of the curve to the midpoint of the long chord joining the point of curvature and point of tangenoy. в. 7.19 m b. 8.12 m c. 9.35 m d. 10.11 m c.) If the stationing of the point of curvature is at 10 + 020, compute the stationing of a point on the curve which intersects with the line making a deflection angle of 8° with the tangent through PC. a. 10+0730.56 b. 10+042.46 c. 10+050.50 d. 10+073.33
A simple curve has a central angle of 38° and a degree of curve of 6". a.) Find the nearest distance from the midpoint of the curve to the point of intersection of the tangents. a. 10.27 m b. 9.83 m c. 8.47 m d. 7.27 m b.) Compute the distance from the midpoint of the curve to the midpoint of the long chord joining the point of curvature and point of tangenoy. в. 7.19 m b. 8.12 m c. 9.35 m d. 10.11 m c.) If the stationing of the point of curvature is at 10 + 020, compute the stationing of a point on the curve which intersects with the line making a deflection angle of 8° with the tangent through PC. a. 10+0730.56 b. 10+042.46 c. 10+050.50 d. 10+073.33
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A simple curve has a central angle of 38* and a degree of curve of 6*.
a.) Find the nearest distance from the midpoint of the curve to the point of intersection of the tangents.
а. 10.27 m
b. 9.83 m
c. 8.47 m
d. 7.27 m
b.) Compute the distance from the midpoint of the curve to the midpoint of the long chord joining the point of curvature and point of tangency.
a. 7.19 m
b. 8.12 m
c. 9.35 m
d. 10.11 m
c.) If the stationing of the point of curvature is at 10 + 020, compute the stationing of a point on the curve which intersects with the line making a deflection angle of 8° with the tangent
through PC.
a. 10+0739.58
b. 10+042.46
c. 10+059.56
d. 10+073.33
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