A simple circular curve is specified with a 12° degree (arc basis) horizontal curve and e=0.08. A structure is proposed on land on the inside of the curve. Assume the road is on level grade. Determine the minimum distance allowable between the proposed structure and the centerline of the curve such that the current maximum safe speed of the curve would not be reduced. (assume radius = 500) Use coefficient of side friction = 0.13

A simple circular curve is specified with a 12° degree (arc basis) horizontal curve and e=0.08. A structure is proposed on land on the inside of the curve. Assume the road is on level grade. Determine the minimum distance allowable between the proposed structure and the centerline of the curve such that the current maximum safe speed of the curve would not be reduced. (assume radius = 500) Use coefficient of side friction = 0.13

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: A horizontal curve is to be designed for a two-lane road in mountainous terrain. The following data…

A: GIVEN- Intersection angle=60 degrees tangent length = 813.10 ft station of PI=2,700 + 10.65 fs =…

Q: A vertical curve is required for a 1st class 3x3 highway section with entering and exiting grades of…

A: The entering and exiting grades of + 5.10% and -6.40%, respectively.The point of intersection of the…

Q: A vertical curve is needed to join to tangents; G₁=0% and G₂=-5%. Assuming a level grade (0%) for…

A: Vertical curves are formed when two different gradients meet at a point. If convexity of curve is…

Q: A rising grade of 1.5 percent meets a falling grade of 4.0 percent at station 2+400 of elevation…

Q: has a radius of 550 ft = 6% A rural highway Max Superetevation Safe side friction factor = 0.17…

A: Radius (R) = 550 ft = 167.64 mMaximum supervision (emx) = 6% = 0.06Firction factor (f) = 0.17

Q: A two-lane rural highway has a horizontal curve segment that must have a radius of 329 ft (measured…

A: Answer We are given Radius = 329 ft Design speed v = 25 mph coefficient of friction f = 0.10 lane…

Q: What is the elevation of the low point?

Q: A horizontal curve is to connect PC on freeway B and PT on freeway A to serve traffic turning from…

Q: A vertical curve is required for a 1st class 3x3 highway section with entering and exiting grades of…

A: Given Data:Design speed Perception-reaction time Friction factor Entering grade: Exiting grade:…

Q: An equal-tangent crest vertical curve is designed for 45 mi/h. The high point is at elevation 380.10…

A: Solution Given That G1=+1.90%G2=-3.10%

Q: (TRAFFIC AND HIGHWAY ENGINEERING) A highway segment has an equal-tangent sag curve and a horizontal…

Q: 4. There is a vertical curve. The grade into the curve +3.2% and the grade out of the curve is…

Q: Design a vertical curve connecting PVI₁ (station = 4+980, Elevation = 198 m), PVI₂ (station = 5+990,…

A: PVI₁ (station = 4+980, Elevation = 198 m) PVI₂ (station = 5+990, Elevation = 163 m) and PVI₃…

Q: The design speed for a two-lane highway (lane width=12 ft.) is 60 mph. The local jurisdiction…

Q: For a sag vertical curve , (g1= -2.5%), (g2=+2.9%), the design speed (55 mile/hr.). The minimum…

A: Given data Grade 1, g1=-2.5% Grade 2, g2=2.9% Design speed=55mi/hr

Concept explainers

Curve setting

A curve is a turn that is provided horizontally or vertically in the design of highways, railways, and runways. A curve connects two straight lines that are separated by the deflection angle. It helps to change the direction and alignment of the highways, railway tracks, and runways. Therefore, the gradual change in their alignment is made by using a curve to provide comfort to the passengers and this also provides an easy turn to change the direction of the moving vehicle.

Question

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Given Data

VIEW

Calculation of maximum speed on curve

VIEW

Calculation of stopping sight distance

VIEW

Horizontal Sight (M)

VIEW

Step by step

Solved in 4 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

A vertical curve is needed to join to tangents; G1=0% and G2= -5%. Assuming a level grade (0%) for braking, and the AASHTO recommended values for deceleration and perception-reaction time, calculate the minimum length of curve (ft) needed to satisfy the safety criteria. The design speed is 70 mph.
Design a vertical summit parabolic curve connecting two tangent grades, a 5% grade intersecting a -3.4% grade at station 1 + 990 with an elevation 42.30 meters. The parabolic curve shall conform with the following safe stopping sight distance requirements. Design velocity = 60 kph Height of driver’s eye from the road pavement = 1.37 meters Height of an object over the pavement ahead = 100 mm. Perception/reaction time = 0.75 second Coefficient of friction between the road pavement and the tires = 0.15 Determine the following: Stopping sight distance The length of the curve The elevation of the highest point on curve.
An equal-tangent vertical curve connects a +3.2 % and a -1.1 % grade. The PVI is at station 100+20 and elevation 950 ft and the PVT is at station 105+20. Answer the following 5 questions Question 3 to Question 7. The station of the PVC is at: sta 93+20 sta 95+20 sta 97+20 sta 99+20 sta 105+20
A vertical curve is needed to join to tangents; G1=1% and G2=4%. Assuming a level grade (0%) for braking, and the AASHTO recommended values for deceleration and perception-reaction time, calculate the minimum length of curve (ft) needed to satisfy the safety criteria. The design speed is 60 mph.
A vertical curve is required to join a road with + 2.5% grade to a road with -3% grade. The design speed of the road is 90 kmph and safe stopping sight distance is 180 m on the road. The coordinates of VPI is (500 m, 100 m), with respect to a fixed bench mark. The horizontal co-ordinate of highest point of curve with respect to fixed benchmark is m. (rounded off to two decimal place)
Please help with this question. Thanks.
A vertical curve is needed to join to tangents; G₁=1% and G2-4%. Assuming a level grade (0%) for braking, and the AASHTO recommended values for deceleration and perception-reaction time, calculate the minimum length of curve (ft) needed to satisfy the safety criteria. The design speed is 60 mph. Response Feedback: G2-G₁ is positive, therefore a sag curve. A=3 SSD(0%)=565.5 ft If you assume SL, Lmin-340 ft. SSD is greater than Lmin. The assumption is good.