(a) Similar matrices have the same characteristic polynomial. (b) Similar matrices have the same eigenvectors. (c) If A is diagonalizable, then the columns of A are linearly independent. (d) If v is an eigenvector of eigenvalue 5, then –v is eigenvector of eigenvalue –5.
(a) Similar matrices have the same characteristic polynomial. (b) Similar matrices have the same eigenvectors. (c) If A is diagonalizable, then the columns of A are linearly independent. (d) If v is an eigenvector of eigenvalue 5, then –v is eigenvector of eigenvalue –5.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![(a) Similar matrices have the same characteristic polynomial.
(b) Similar matrices have the same eigenvectors.
(c) If \( A \) is diagonalizable, then the columns of \( A \) are linearly independent.
(d) If \( \mathbf{v} \) is an eigenvector of eigenvalue \( 5 \), then \( -\mathbf{v} \) is an eigenvector of eigenvalue \( -5 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1c145f92-040a-49d6-acdb-06a5c78bf220%2F7e7857a1-ddf7-4da3-bc80-03fd562a21c2%2F3byeu3_processed.png&w=3840&q=75)
Transcribed Image Text:(a) Similar matrices have the same characteristic polynomial.
(b) Similar matrices have the same eigenvectors.
(c) If \( A \) is diagonalizable, then the columns of \( A \) are linearly independent.
(d) If \( \mathbf{v} \) is an eigenvector of eigenvalue \( 5 \), then \( -\mathbf{v} \) is an eigenvector of eigenvalue \( -5 \).
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