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A silicon crystal having a cross-sectional area of 0.002 cm² and a length of 0.01 cm is connected across a 20-V battery. At T = 300 K, a current of 0.25 A in the semiconductor is required. Calculate the required conductivity and use that to determine the density of donor atoms to be added to achieve this conductivity. Nd= 2.31 X 10¹4 cm-3 Nd= 3.09 X 1014 cm-3 Nd=2.89 X 1014 cm-3 Nd=4.63 X 1014 cm-3

A silicon crystal having a cross-sectional area of 0.002 cm² and a length of 0.01 cm is connected across a 20-V battery. At T = 300 K, a current of 0.25 A in the semiconductor is required. Calculate the required conductivity and use that to determine the density of donor atoms to be added to achieve this conductivity. Nd= 2.31 X 10¹4 cm-3 Nd= 3.09 X 1014 cm-3 Nd=2.89 X 1014 cm-3 Nd=4.63 X 1014 cm-3

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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A silicon crystal having a cross-sectional area of 0.002 cm² and a length of 0.01 cm is connected across a 20-V battery. At T = 300 K, a current of 0.25 A in the semiconductor is required. Calculate the required conductivity and use that to determine the density of donor atoms to be added to achieve this conductivity. Nd= 2.31 X 1014 cm-3 Nd = 3.09 X 1014 cm -3 Nd= 2.89 X 1014 cm-3 Nd=4.63 X 10¹4 cm-3
Transcribed Image Text:A silicon crystal having a cross-sectional area of 0.002 cm² and a length of 0.01 cm is connected across a 20-V battery. At T = 300 K, a current of 0.25 A in the semiconductor is required. Calculate the required conductivity and use that to determine the density of donor atoms to be added to achieve this conductivity. Nd= 2.31 X 1014 cm-3 Nd = 3.09 X 1014 cm -3 Nd= 2.89 X 1014 cm-3 Nd=4.63 X 10¹4 cm-3
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