A shunt motor is connected to 230V line and running at 1000r/min. Armature current is 60A and total armature resistance is 0.15. Armature is lap-wound with 83 slots and 6 turns per coil. Calculate, (i) (ii) (iii) Mechanical power of the motor in KW and HP (iv) Torque developed by the motor (v) CEMF Conductor loss Flux per pole (vi) Efficiency of the motor

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Draw the circuit please. 

A shunt motor is connected to 230V line and running at 1000r/min. Armature current is 60A
and total armature resistance is 0.15N. Armature is lap-wound with 83 slots and 6 turns per
coil. Calculate,
(i)
(ii)
(iii) Mechanical power of the motor in KW and HP
(iv) Torque developed by the motor
(v)
(vi) Efficiency of the motor
CEMF
Conductor loss
Flux per pole
Transcribed Image Text:A shunt motor is connected to 230V line and running at 1000r/min. Armature current is 60A and total armature resistance is 0.15N. Armature is lap-wound with 83 slots and 6 turns per coil. Calculate, (i) (ii) (iii) Mechanical power of the motor in KW and HP (iv) Torque developed by the motor (v) (vi) Efficiency of the motor CEMF Conductor loss Flux per pole
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Given information:

A shunt motor is lap-wound with 83 slots and 6 turns per phase.

The supply voltage across which motor is connected is Vt=230 Volts.

The speed of the motor is N=1000 rpm.

Total armature resistance is Ra=0.15 Ω.

Armature current is Ia=60 A.

Since brush voltage drop is not given so we can ignore it.

We need to determine CEMF, conductor loss and mechanical power of the motor in KW and HP.

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