(a) Show that y = 3a²x - x³ is strictly increasing for a < x < a and that on this interval y increases from -2a³ to 2a³. (b) By putting x = 2a sin and using the identity sin³ = (3 sin - sin 30)/4, show that the equation becomes y = 2a³ sin 36 and hence that x(y) = 2a sin -1 (1/7 sin-¹ (203)). 3
(a) Show that y = 3a²x - x³ is strictly increasing for a < x < a and that on this interval y increases from -2a³ to 2a³. (b) By putting x = 2a sin and using the identity sin³ = (3 sin - sin 30)/4, show that the equation becomes y = 2a³ sin 36 and hence that x(y) = 2a sin -1 (1/7 sin-¹ (203)). 3
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:(a) Show that y = 3a²x - x³ is strictly increasing for a < x < a
and that on this interval y increases from -2a³ to 2a³.
(b) By putting x = 2a sin and using the identity sin³
that the equation becomes
y = 2a³ sin 30 and hence that x(y)
=
=
(3 sin sin 30)/4, show
2a sin sin
-1
2a3
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