(a) Show that r= 3 is a solution of 3z 15+ 17z + 3 = 0. (b) Hence name the theorem that allows us to write 3. (r-3) (br + cz+ d) 15 + 17r +3 0 as 0 where 6, c and d are numbers. c) Use long polynomial division to show that b= 3,c=-6 and d = -1. d) Complete the square for the expression 3-62-1 and find the coordinates of its extremum.

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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7. (a) Show that z= 3 is a solution of 3.r
15+ 17z +3 = 0.
(b) Hence name the theorem that allows us to write 3.– 15z + 17z +3=0 as
(z-3) (br + cz+ d)0 where 6, cand d are numbers.
(c) Use long polynomial division to show that - 3,c -6 and d= -1.
(d) Complete the square for the expression 3-6z-1 and find the coordinates
of its extremum.
Transcribed Image Text:7. (a) Show that z= 3 is a solution of 3.r 15+ 17z +3 = 0. (b) Hence name the theorem that allows us to write 3.– 15z + 17z +3=0 as (z-3) (br + cz+ d)0 where 6, cand d are numbers. (c) Use long polynomial division to show that - 3,c -6 and d= -1. (d) Complete the square for the expression 3-6z-1 and find the coordinates of its extremum.
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