a) Show that P(E) =1-P(E). b) if the probability that an automobile mechanic will service 3, 4, 5, 6, 7 or 8 or more cars on any given workday are respectively 0.12, 0.19, 0.28, 0.24, 0.10, and 0.07. Calculate the probability that he will service at least 4 cars on his next day at work.

a) Show that P(E) =1-P(E). b) if the probability that an automobile mechanic will service 3, 4, 5, 6, 7 or 8 or more cars on any given workday are respectively 0.12, 0.19, 0.28, 0.24, 0.10, and 0.07. Calculate the probability that he will service at least 4 cars on his next day at work.

Name: Q1.a) Show that P(E) =1-P(E).b) if the probability that an automobile
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Description: Q1.a) Show that P(E) =1-P(E).b) if the probability that an automobile mechanic will service 3, 4, 5, 6, 7 or 8 or more cars on anygiven workday are respectively 0.12, 0.19, 0.28, 0.24, 0.10, and 0.07. Calculate the probabilitythat he will service at

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Concept explainers

Contingency Table

A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear relationship between two variables. A contingency table is indeed a type of frequency distribution table that displays two variables at the same time.

Binomial Distribution

Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.

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Q1.
a) Show that P(E) =1-P(E).
b) if the probability that an automobile mechanic will service 3, 4, 5, 6, 7 or 8 or more cars on any
given workday are respectively 0.12, 0.19, 0.28, 0.24, 0.10, and 0.07. Calculate the probability
that he will service at least 4 cars on his next day at work.

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