(a) Show that e>1+ x if x> 0. [Hint: Show that f(x) = e* – (1 + x) is increasing for x> 0.] (b) Deduce that s e**dx < e.

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Question
(a) Show that e>1+ x if x> 0.
[Hint: Show that f(x) = e* – (1 + x) is increasing
for x> 0.]
(b) Deduce that s e**dx < e.
Transcribed Image Text:(a) Show that e>1+ x if x> 0. [Hint: Show that f(x) = e* – (1 + x) is increasing for x> 0.] (b) Deduce that s e**dx < e.
Expert Solution
Step 1

If x0 as exp is increase we have ex1. they by means value theorem there exist c0,x such that

                             ex-1=ecx

Thus

                            exx+1

If x-1, we have

                           ex0>1+x

Now if -1<x<0 we have

                         ec<1-ec>-1-ecx<-x

Thus

                      1-ex=ec(-x)<-x

and

                    ex>1+x

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