A shot putter threw an 8 lb 13 oz shot 60 ft, 10 in. Assuming the shot putter launched the shot at a 40° angle to thehorizontal from 5.5 ft above the ground, what was the shot's initial speed? The acceleration due to gravity is 32 ft/sec².The shot's initial speed was vo=ft/sec.(Do not round until the final answer. Then round to the nearest tenth as needed.)

Answered: A shot putter threw an 8 lb 13 oz shot…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A shot putter threw an 8 lb 13 oz shot 60 ft, 10 in. Assuming the shot putter launched the shot at a 40° angle to the
horizontal from 5.5 ft above the ground, what was the shot's initial speed? The acceleration due to gravity is 32 ft/sec².
The shot's initial speed was vo
=
ft/sec.
(Do not round until the final answer. Then round to the nearest tenth as needed.)

Expert Solution

Step 1

To solve this problem, we can use the kinematic equations of motion. We can assume that the shot was launched horizontally, so the initial vertical velocity is zero. Therefore, we can focus on the horizontal motion of the shot.

First, let's convert the weight of the shot to mass:

m = 8 lb 13 oz = 8.8125 lb = 3.994 kg

Next, let's convert the distance and height to SI units:

d = 60 ft + 10 in = 60.83 ft = 18.5514 m h = 5.5 ft = 1.6764 m

Now, we can use the following kinematic equation to find the initial speed of the shot:

d = vo * cos(theta) * t

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