A shopper pushes a 7.4 kg cart at constant of 1.20 m/s speed along a rough horizontal surface by applying a force of 23.6 N at an angle of 39.4° below the horizontal. What is the coefficient of kinetic friction between the cart and the surface? V Fa O 0.251 O 0.317 0.208 O 0.325
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- Thanks!A desperate hiker has to think fast to help his friend who has fallen below him. Quickly, he ties a rope to a rock of mass ma and makes his way over the ledge (see the figure). If the coefficient of maximum static friction between the rock and the ground is µ, and the mass of the hiker is mâ, what is the maximum mass of the friend, mc, that the rock can hold so the hikers can then make their way up over the ledge? Assume the rope is parallel to the ground and the point where the rope passes over the ledge is frictionless. mc = JuA block with mass m starting from rest at point A is sliding down a rough incline with kinetic coefficient of friction µ. The incline has angle 0 with respect to the horizontal sur- face. As the block slides down for a distance O 1. KB = m gs cos 0 – µ mgs cos 0 8, it passes point B. O 2. KB = mgs sin 0 + µ m gs sin 0 O 3. KB = mgs cos0 – µm gs sin 0 m O 4. KB = mgs sin 0 + µ mgs cos 0 v =0 O 5. KB = mgs sin 0 – µm g s sin 0 m О6. Кв — тgs sin@ — дтдs cos® B O 7. KB = m gs cos 0 + µ mgs cos 0 O 8. KB = m gs cos 0 + µ mgs sin 0 Find the kinetic energy of the block as it passes B.
- A block is being pulled up an inclined plane by a force with magnitude F=45.0 N as shown In the figure above. The block has a mass of m =1.35 kg. The coefficient of kinetic friction between the block an the surface of the incline plane is µ = 0.287. The inclined plane makes an angle \theta= 31.7 degrees with respect to the horizontal. What is the magnitude of the acceleration of the mass?A constant applied force ?p of 15.0 N pushes a box with a mass ?=7.00 kg a distance x=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is 0.150. Assuming that the box starts from rest, what is the final velocity ?f of the box at the 15.0 m point? If there were no friction between the box and the floor, what applied force Fnew would give the box the same final velocity?A skier starts from rest at the top of a hill that is inclined at 10.0° with respect to the horizontal. The hillside is 190 m long, and the coefficient of friction between snow and skis is 0.0750. At the bottom of the hill, the snow is level and the coefficient of friction is unchanged. How far does the skier glide along the horizontal portion of the snow before coming to rest? m
- B95.6An empty sled of mass 25 kg slides down a muiddy hill with a constant speed of 2.4 m/s The slope of the hill is inclined at an angle of 15 degrees with the horizontal. a. Calculate the frictional force on the sled as it slides down the slope b.Calculate the coefficient of friction between the sled and the muddy surface of the slope c. The sled reaches the bottom of the slope and continues of horizontal ground. Assume the same coefficient of friction. In terms of velocity and acceleration, describe the motion of the sled as it travels on horizontal ground.
- A fish of mass 1kg is lying still on an inclined plane at 3o degrees above the horizontal. the magnitude of the normal force exerted by the plane on the fish is. 0N 9.8N 8.5 N 4.9NVf A bale of cardboard to be recycled thrown down an incline (0 = 25°) at A with a velocity of 1.30 m/s. The bale slides along the surface ABC to a conveyor belt that moves with a velocity of 1.75 m/s. The distance along the inclined surface is dab = 7.0 m and the flat surface dBc = - 5 m. The coefficient of kinetic friction is k 0.25 between the bale and all surfaces. 0 = B dBc Determine: (a) the speed of the bale at C (b) the distance the bale slides on the conveyor belt before it comes to rest relative to the belt. dAB T 1 Vi AProblem 7: A block of mass m = 59 kg slides along a horizontal surface. The coefficient of friction between the block and the surface is u = 0.29. The block has an initial speed of v, = 18 m/s in the positive x-direction as shown. m