A sharp shooter at a Wild West show impresses the crowd with her marksmanship. For her first trick, she throws a block of wood 5 m above the ground directly over her head and then fires at it with her pistol right when the wood's upward velocity goes to 0 m/s. The mass of the bullet is M, = 5 g and the mass of the wood is Mw = ½ kg, so you may use the fact that Mb < M» throughout this problem. You may also neglect the force of gravity acting on the bullet (but not on the wood block) throughout the problem. a) If the block rises another 1.8 m after the bullet becomes lodged in the wood, then what was the speed of the block immediately after it was struck by the bullet? b) How fast was the bullet moving immediately before it struck the block? c) During the collision between the bullet and the block, what fraction of the initial kinetic energy of the bullet was converted into kinetic energy of the block? If you couldn't find the answer to part b), use the value v = 500 m/s for the bullet's initial velocity for the rest of the problem. d) Just as the block's upward velocity decreases to 0 m/s again, the sharp shooter fires again and hits the block, but this time the bullet breaks through the wood and is traveling at a speed of 400 m/s upwards after the collision. What is the speed of the block immediately after the bullet broke through it? e) Just as the block reaches its highest point after being shot two times, the sharp shooter fires a rubber bullet at the block so that the bullet bounces elastically off of the bottom of the block. How much higher does the block go after being struck by the rubber bullet assuming that the rubber bullet has the same mass and travels at the same speed leaving the pistol as the regular bullet in part b)? %3D wood block - bulet pistol-a sharp shooter
A sharp shooter at a Wild West show impresses the crowd with her marksmanship. For her first trick, she throws a block of wood 5 m above the ground directly over her head and then fires at it with her pistol right when the wood's upward velocity goes to 0 m/s. The mass of the bullet is M, = 5 g and the mass of the wood is Mw = ½ kg, so you may use the fact that Mb < M» throughout this problem. You may also neglect the force of gravity acting on the bullet (but not on the wood block) throughout the problem. a) If the block rises another 1.8 m after the bullet becomes lodged in the wood, then what was the speed of the block immediately after it was struck by the bullet? b) How fast was the bullet moving immediately before it struck the block? c) During the collision between the bullet and the block, what fraction of the initial kinetic energy of the bullet was converted into kinetic energy of the block? If you couldn't find the answer to part b), use the value v = 500 m/s for the bullet's initial velocity for the rest of the problem. d) Just as the block's upward velocity decreases to 0 m/s again, the sharp shooter fires again and hits the block, but this time the bullet breaks through the wood and is traveling at a speed of 400 m/s upwards after the collision. What is the speed of the block immediately after the bullet broke through it? e) Just as the block reaches its highest point after being shot two times, the sharp shooter fires a rubber bullet at the block so that the bullet bounces elastically off of the bottom of the block. How much higher does the block go after being struck by the rubber bullet assuming that the rubber bullet has the same mass and travels at the same speed leaving the pistol as the regular bullet in part b)? %3D wood block - bulet pistol-a sharp shooter
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PM2: please answer question and explain each step with reasoning
Transcribed Image Text:A sharp shooter at a Wild West show impresses the crowd with her marksmanship. For her first trick, she
throws a block of wood 5 m above the ground directly over her head and then fires at it with her pistol right
when the wood's upward velocity goes to 0 m/s. The mass of the bullet is M, = 5 g and the mass of the wood
is Mw = ½ kg, so you may use the fact that Mp < M» throughout this problem. You may also neglect the force
of gravity acting on the bullet (but not on the wood block) throughout the problem.
a) If the block rises another 1.8 m after the bullet becomes lodged in the wood, then what was the speed of the
block immediately after it was struck by the bullet?
b) How fast was the bullet moving immediately before it struck the block?
c) During the collision between the bullet and the block, what fraction of the
initial kinetic energy of the bullet was converted into kinetic energy of the
block? If you couldn’t find the answer to part b), use the value v = 500 m/s
for the bullet's initial velocity for the rest of the problem.
d) Just as the block's upward velocity decreases to 0 m/s again, the sharp
shooter fires again and hits the block, but this time the bullet breaks through
the wood and is traveling at a speed of 400 m/s upwards after the collision.
What is the speed of the block immediately after the bullet broke through it?
e) Just as the block reaches its highest point after being shot two times, the
sharp shooter fires a rubber bullet at the block so that the bullet bounces
elastically off of the bottom of the block. How much higher does the block
go after being struck by the rubber bullet assuming that the rubber bullet has
the same mass and travels at the same speed leaving the pistol as the regular
bullet in part b)?
%3D
wood
- block
- bulle t
pistol-as
sharp
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