A series of modified Proctor tests have been performed on a soil that has a G, of 2.68. The test results obtained are as follows. Point Weight of Compacted Soil + Moisture Content Test Results Mass of Mass of Can + Mass of Can + Dry No. Mold (lb) Can (g) Moist Soil (g) Soil (g) 12345 8.73 22.13 207.51 202.30 9.07 25.26 239.69 225.27 9.40 19.74 253.90 230.64 9.46 23.36 250.93 219.74 9.22 20.28 301.47 250.95 The weight of the empty mold was 5.06 lb. Plot the laboratory test results and the S = 80% and S = 100% curves, and then draw the modified Proctor compaction curve. Determine the maximum dry unit weight (lb/ft³) and the optimum moisture content, based on the modified Proctor test. Assuming that the field compaction curve is the same as the compaction curve obtained using the modified Proctor test, determine the range of as-compacted moisture content required in the field to obtain a relative compaction of at least (a) 90%, and (b) 95%.

A series of modified Proctor tests have been performed on a soil that has a G, of 2.68. The test results obtained are as follows. Point Weight of Compacted Soil + Moisture Content Test Results Mass of Mass of Can + Mass of Can + Dry No. Mold (lb) Can (g) Moist Soil (g) Soil (g) 12345 8.73 22.13 207.51 202.30 9.07 25.26 239.69 225.27 9.40 19.74 253.90 230.64 9.46 23.36 250.93 219.74 9.22 20.28 301.47 250.95 The weight of the empty mold was 5.06 lb. Plot the laboratory test results and the S = 80% and S = 100% curves, and then draw the modified Proctor compaction curve. Determine the maximum dry unit weight (lb/ft³) and the optimum moisture content, based on the modified Proctor test. Assuming that the field compaction curve is the same as the compaction curve obtained using the modified Proctor test, determine the range of as-compacted moisture content required in the field to obtain a relative compaction of at least (a) 90%, and (b) 95%.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Q16. The data in the accompanying table resulted from performing Standard Proctor Tests on a soil. Plot the data and determine the soil's laboratory optimum moisture content. Dry Density Ib/ft3 Moisture Content 12 103.1 14 106.2 16 108.9 18 112.8 20 110.5 22 105.5
Problems 5.1 The results of a standard Proctor test are given below. Determine the mar imum dry unit weight of compaction and the optimum moisture content. Weight of wet soil Volume of Moisture in the mold (N) Proctor mold content (cm') (%) 943 14.5 8.4 943 18.46 10.2 943 20.77 12.3 943 17.88 14.6 943 16.15 16.8 5.2 For the soil described in Problem 5.1, if G. = 2.72, determine the void ratio and the degree of saturation at optimum moisture content.
1. The results of a standard Proctor test are given in Table Q1 below. Determine the maximum dry density of soil compaction and the optimum moisture content. Table Q1 Volume of Proctor Mass of wet soil in the mold Moisture content mold (cm³) (kg) 3.39 (%) 11.5 987 987 3.87 13.5 987 4.22 15.5 987 5.11 17.5 987 4.75 19.5 987 4.31 21.5
The following data were obtained from sand-cone experiment where a volume of a certain soil is replaced with a sand in order to find the density of the soil. Density of sand used in test = 1.3 g/cc Wt. Of soil excavated from the pit = 925 g Wt. of sand filling the pit = 675 g Water content of natural soil = 15% Specific gravity of Solid = 2.7 a) Determine the wet density of the soil in g/cc. b) Determine the dry density of the soil in g/cc. c) What is the porosity of the soil?
76 .ll Q3.png The data from standard and modified proctor test on a soil sample (density of solids: 2680 kg/m3 ) are provided below: Standard proctor test Modified proctor test Dry density (kg/m) 1691 Dry density (kg/m') 1873 Water content (%) Water content (%) 9.3 9.3 1715 11,8 1910 12.8 1755 14.3 1803 15.5 1747 17.6 1699 18.7 1685 20.8 1641 21.1 1619 23 a) Plot the compaction curves (both standard and modified in one graph). b) Establish the maximum dry density and optimum water content for each test.
The following results were obtained by a mechanical sieve analysis. classify the soil using the Unified Soil Classification System. Sieve analysis % passing by weight is as follows: No.4 = 100% No. 40 = 96% No.200 = 52% Liquid Limit= 29 Plastic Limit = 11
The following data were obtained from a soil sample. Determine the degree of saturation. MOISTURE CONTENT DETERMINATION |Sample 1 Sample 2 Sample 3 48.2 Wt of tin cup (g) Wt. of tin cup + Wet Soil (g) Wt. of tin cup and dry soil (g) 50.1 53.3 118.1 126.7 121.5 103.6 109.4 107.6 UNIT WEIGHT DETERMINATION Wt of wet soil (g) Wt of wet soil + paraffin (g) Volume of wet soil + paraffin (mL) 158.6 165.0 101.4 SPECIFIC GRAVITY OF SOLIDS DETERMINATION Wt of pycnometer (g) Wt of pycnometer + solids (g) Wt of water-filled pycnometer (g) Wt of pycnometer + solids + water (g) 102.0 206.0 339.0 405.6 71.1% 74.9% 68.3% O 75.6%
Following are the results of a field unit-weight determination test performed on the same soil by means of the sand cone method: -Calibrated dry unit weight of Ottawa sand = 15.4019 kn/m3 -Calibrated weight of Ottawa sand to fill the cone = 5.3496 N -Weightof jar + cone + sand (before use) = 74.451 N -Weightof jar + cone + sand (after use) = 46.886 N -Weight of moist soil from hole = 29.509 N -Moisture content of moist soil = 10.21% DETERMINE AND SHOW COMPLETE SOLUTION 1. Dry density of compaction in the field in kg/cu.m.
The following results were obtained by a mechanical sieve analysis. classify the soil using the Unified Soil Classification System. Sieve analysis % passing by weight is as follows: No.4 = 100% No. 40 = 89% No.200 = 65% Liquid Limit= 44 Plastic Limit = 23
4. The results of liquid limit testing on 3 samples of a soil are shown below. sample 1. 2 3 mass (g) 20 mass mass (g) emply can (M.) wet soil + can (M.) dry soil + can (M) moisture content: w (%) Number of cranks 20 20 35 35 28.82 36 28.15 30.38 4 10 30 Calculate the moisture content of cach of the 3 samples. Show your calculations below and then put your answers in the chart above. M,- M, м, - м, x100%
5. The following information is obtained from a sieve analysis to determine the range of particle sizes in a granular soil sample. Sieve Size Sieve Opening (4.76) Percent Finer#4 4.76 96#10 2.00 80#20 0.84 51#40 0.42 38#60 0.25 25#100 0.149 12#200 0.074 5 Present the information as grain-size curve on semi-logarithmic coordinates of percent finer against particle size diameter. From the plot, determine the uniformity coefficient Cu.
1. A dry sand is placed in a container having a volume of 0.0092 cubic centimeter. The dry unit weightof the sample is 0.015 gram. Water is carefully added to the container so as not to disturbed thecondition of the sand. When the container is filled, the combined weight of soil plus water is 0.0182gram.a. Determine the specific gravity of soil particle.b. Determine the dry unit weight of soil.2. If the soil sample has a water content of 11% and a unit weight of 19.67 kN/m3 , determine thepercentage of air in voids and the degree of saturation if the specific gravity of soil solid is 2.75.3. If the soil sample has a specific gravity of 2.71 and a porosity of 0.345, determine the saturated unitweight and the bouyant unit weight.4. A soil sample having a liquidity index of 0.85, a plasticity index of 16.50 and a plastic limit of 11.45.The soil sample has a specicfic gravity of 2.68 and a void ratio of 0.77.a. Compute the degree of saturation.b. Compute the air void ratio.