A series circuit contains an inductor, a resistor, and a capacitor for which L = 0.5h, R = 102, and C = 0.01f , respectively. s10, 05 The voltage E (t) = {0" instantaneous charge q (t)on the capacitor for t > 0, if q (0) = 0 and d (0) = 0 is applied to the circuit. Determine the O q(t) = 10- 10 cos(10t) – e-10t sin(10t) – -e-10(t-5) cos(10 (t – 5)) – me-10(t-6) sin(10 (t – 5))] U (2 – 5) -10t е O g (t) 3D3-글e과 cos(26)-글e-2 sin(2t)- [높 - 놀e-2(-5) cos(2 (t -5)) - 글어-3) sin(2 (t-5)] U(t-5) -2(t-5) O q(t) = 1- e-10t cos(10t) e-10t sin(10t) – [1-e-10(t-5) cos(10 (t – 5)) – e-10(t-5) sin(10 (t – 5))] U (t – 5) Og (t) %3D -공e-와 cos(5t)-1e-st sin(5t)- [끊-좋e-st-5) cos(5 (t - 5)) - 금e- St-5) sin(5 (t-5)] U(t -5)

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
Section: Chapter Questions
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16) Please help with following multiple choice ASAP!

A series circuit contains an inductor, a resistor, and a capacitor for which
= 0.01f, respectively.
L = 0.5h, R = 10N, and C
The voltage E (t) = {o"
{o. t25
s10,
0<t<5
is applied to the circuit. Determine the
instantaneous charge q (t)on the capacitor for t > 0, if q (0) = 0 and
q (0) = 0
O q (t) = 10
- be-10t cos(10t) – e-10t sin(10€) – [ - e-10t-5) cos(10 (t – 5)) – e-10(t-5) şin(10 (t – 5))] U (t – 5)
te-10(t-5) cos(10 (t – 5)) - e-10(t-5) sin(10 (t – 5))]U (t – 5)
COS
Og(t) =D-e-과 cos(2t)-글e-2 sin(2t)-[-글e-2(-8) cos (2 (t-5))-글1e-26-5) sin(2 (t-5))] U (t -5)
O q(t)
-2(t-5) sin(2 (t – 5))] U (t – 5)
O q (t) = 1- e-10t cos(10t) – e-10t sin(10t) – [1- e-10(t-5) cos(10 (t - 5)) – e-10(t-5) sin(10 (t – 5))] U (t - 5)
O q(t) = -te-5t cos(5t) – e-5t sin(5t) – - te-5(-5) cos(5 (t – 5)) – e-5(t-5) sin(5 (t – 5)] U (t – 5)
1/2
Transcribed Image Text:A series circuit contains an inductor, a resistor, and a capacitor for which = 0.01f, respectively. L = 0.5h, R = 10N, and C The voltage E (t) = {o" {o. t25 s10, 0<t<5 is applied to the circuit. Determine the instantaneous charge q (t)on the capacitor for t > 0, if q (0) = 0 and q (0) = 0 O q (t) = 10 - be-10t cos(10t) – e-10t sin(10€) – [ - e-10t-5) cos(10 (t – 5)) – e-10(t-5) şin(10 (t – 5))] U (t – 5) te-10(t-5) cos(10 (t – 5)) - e-10(t-5) sin(10 (t – 5))]U (t – 5) COS Og(t) =D-e-과 cos(2t)-글e-2 sin(2t)-[-글e-2(-8) cos (2 (t-5))-글1e-26-5) sin(2 (t-5))] U (t -5) O q(t) -2(t-5) sin(2 (t – 5))] U (t – 5) O q (t) = 1- e-10t cos(10t) – e-10t sin(10t) – [1- e-10(t-5) cos(10 (t - 5)) – e-10(t-5) sin(10 (t – 5))] U (t - 5) O q(t) = -te-5t cos(5t) – e-5t sin(5t) – - te-5(-5) cos(5 (t – 5)) – e-5(t-5) sin(5 (t – 5)] U (t – 5) 1/2
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