A sensor converts flow linearly so that flow rate from 0 to 300 m3/h becomes a current from 0 to 50 mA.(i) Find a linear equation between output current and flow rate.(ii) Calculate the output current when flow rate is 210 m3/h.(iii) The output current increases from 0 to 15 mA in 5 seconds when there is a sudden inrush from 0 to 210 m3/h. What is the sensor time constant? A sensor converts flow linearly so that flow rate from 0 to 300 m³/h becomes acurrent from 0 to 50 mA.(i)Find a linear equation between output current and flow rate.(ii)Calculate the output current when flow rate is 210 m/h.(iii)The output current increases from 0 to 15 mA in 5 seconds when thereis a sudden inrush from 0 to 210 m/h. What is the sensor timeconstant?

Answered: Image /qna-images/answer/ce84dd3a-26d8-43e5-9ea6-5c7657fa2efa.jpg

Answered: A sensor converts flow linearly so that…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Related questions

Concept explainers

Question

A sensor converts flow linearly so that flow rate from 0 to 300 m3/h becomes a current from 0 to 50 mA.
(i) Find a linear equation between output current and flow rate.
(ii) Calculate the output current when flow rate is 210 m3/h.
(iii) The output current increases from 0 to 15 mA in 5 seconds when there is a sudden inrush from 0 to 210 m3/h. What is the sensor time constant?

A sensor converts flow linearly so that flow rate from 0 to 300 m³/h becomes a
current from 0 to 50 mA.
(i)
Find a linear equation between output current and flow rate.
(ii)
Calculate the output current when flow rate is 210 m/h.
(iii)
The output current increases from 0 to 15 mA in 5 seconds when there
is a sudden inrush from 0 to 210 m/h. What is the sensor time
constant?

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.

Similar questions