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A semicircular (radius = r) arc-shaped earrings. Is hung on the yarn pattern. Specify the encounter of the hanging wire and jewelry 90

A semicircular (radius = r) arc-shaped earrings. Is hung on the yarn pattern. Specify the encounter of the hanging wire and jewelry 90

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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A semicircular (radius = r) arc-shaped earrings. Is hung on the yarn pattern. Specify the encounter of the hanging wire and jewelry 90 <icy <180. Tip: The task requires formulas for the curve (or focus) of the curve for the rules; e.g. y = (Vast: 1 So е In what position is it worth calculating the length of the auxiliary triangle category? 122,5°, y ds. | I 1
Transcribed Image Text:A semicircular (radius = r) arc-shaped earrings. Is hung on the yarn pattern. Specify the encounter of the hanging wire and jewelry 90 <icy <180. Tip: The task requires formulas for the curve (or focus) of the curve for the rules; e.g. y = (Vast: 1 So е In what position is it worth calculating the length of the auxiliary triangle category? 122,5°, y ds. | I 1
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An earring made of a homogeneous substance in the shape of a semicircle (radius = R) arc is hung according to the thread pattern. Determine the meeting angle between the hanging wire and the jewelry 90° < p < 180° Hint: The problem requires formulas for the center of the curve (or center of gravity) for line integrals; e.g. y = 1 е Jo y ds. In which position should the length of the side of the auxiliary triangle be calculated? (Answer: 122.5°) | |
Transcribed Image Text:An earring made of a homogeneous substance in the shape of a semicircle (radius = R) arc is hung according to the thread pattern. Determine the meeting angle between the hanging wire and the jewelry 90° < p < 180° Hint: The problem requires formulas for the center of the curve (or center of gravity) for line integrals; e.g. y = 1 е Jo y ds. In which position should the length of the side of the auxiliary triangle be calculated? (Answer: 122.5°) | |
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