A semicircular plate with diameter 12 ft is submerged vertically 3 ft below the surface of the water. Express the hydrostatic force (in Ib) against one side of the plate as an integral (let the positive direction be upwards) and evaluate it. (Round your answer to the nearest whole number. Recall that the weight density of water is 62.5 Ib/ft3.) 28 (11 – dy = 22809 Ib

A semicircular plate with diameter 12 ft is submerged vertically 3 ft below the surface of the water. Express the hydrostatic force (in Ib) against one side of the plate as an integral (let the positive direction be upwards) and evaluate it. (Round your answer to the nearest whole number. Recall that the weight density of water is 62.5 Ib/ft3.) 28 (11 – dy = 22809 Ib

Name: A semicircular plate with diameter 12 ft is submerged vertically 3 ft
Uploaded: 2024-03-20T06:56:55.000Z
Channel: Bartleby
Description: A semicircular plate with diameter 12 ft is submerged vertically 3 ft below the surface of the water.Express the hydrostatic force (in Ib) against one side of the plate as an integral (let the positive direction be upwards) and evaluate it. (Round y

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

A triangular plate with base 6 m and height 2 m is submerged vertically in water such that the highest vertex of the plate is 6 meters below the surface and the base is horizontal to the surface. 6 m 6 m 2 m Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Round your answer to the nearest whole number. Use 9.8 m/s2 for the acceleration due to gravity. Recall that the weight density of water is 1,000 kg/m3.)
1. Determine the hydrostatic force acting on a vertical trapezoidal section whose upper base is flushed parallel to the liquid surface. The top base measures 2 m and the lower base is twice the length of its top. One of its remaining side is upright vertical while the other is inclined 45° with the horizontal. Calculate as well the location of its center of pressure. 6 m 2. The tank shown contains alcohol (SG=o.78) and covered by a diameter Calculate the bydrostatic force E
Give me right solution according to the question.. Read the question carefully. An isosceles triangle is fully submerged vertically in water with its 250mm base below the vertex and parallel to the water surface. The vertex is 50mm from the water surface. If the distance from the centroid of the triangle to the center of pressure (or e) is 48.5632mm, determine the vertical distance from the vertex to the base of the triangle.
A solid sphere has a diameter of 3.81 cm and a relative density of 0.089. It floats in the water a depth "h". determine this height if: a) the buoyancy due to the air is negligible. b) the buoyancy of the air is not negligible ρair=1.225kg/m^3 (use 4 decimal places for your calculations).
right cylindrical object has a diameter of 1526 mm and a height of 2.1m. The density of water is 1000 kg/m3. If the right cylindrical object is placed in the water, what is the buoyant force?
Total Hydrostatic Forces on Submerged Surfaces Fluid Mechanics Determine the hydrostatic force and its location by (a)integration method and (b)formula method. Зт y dy F - 6m 4m
6. The force on the triangular plate that is submerged in water as shown below waters surface 6m 4m is given by F = ["p f(x) dy, where p is the weight density of water Compute a + b + f(2)
1. A metal plate determined by y = x2 submerged in water as show. Find the total hydrostatic force on 16 the plate. You may leave the density of water as p and gravity as g. Give exact answer. (20,25) Gusten Lo woter level metal plate 16
Determine the magnitude and point of application of the horizontal and vertical components of the hydrostatic pressure force acting unit length of the prismatic surface abcdef. (the unit weight of water= 9.81 kN/m3
QUESTION 1 Determine the resultant hydrostatic force on the 1 m square door shown in the figure below, and the force F required to open the door. P = 0.05 MN/m² Po Gas 2 m F -Door -hinge T Water Gas Mercury- Figure 1 500 mm
determine the hydrostatic force in kN acting in an isoceles triangular plate of base 9.11m and altitude of 8.14 m when the plate is immersed vertically in molasses (Specific Gravity= 1.5) the base of the plate is 1.325 m below the free surface of molasses.