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A semi-circular piece of radius r= 400 TRm is removed from a rectangular plate of size a = negligible, therefore the rest of the problem can be handled based of areas. Moment of inertia here refers to the second moment of area, z dm = [2°&A in m rather than kgm 880 mm,b= 480 mn. The thickness is %3D %3D Analyse the part in order to determine the period of free oscillation TA about an axis that is perpendicular to the figure through a point of coordinates A( 202 ,40 ) in mm. The simplest and intuitive splitting of the part in constituting shapes is Area = Area, Areaz with subscript 1 applying to the rectangular part and 2 to the semi-circular one. %3D where h is the distance between point A and the CG. ghArea Calculate the coordinates of the CG in the system of coordinates (z, y). mm thir point onward

A semi-circular piece of radius r= 400 TRm is removed from a rectangular plate of size a = negligible, therefore the rest of the problem can be handled based of areas. Moment of inertia here refers to the second moment of area, z dm = [2°&A in m rather than kgm 880 mm,b= 480 mn. The thickness is %3D %3D Analyse the part in order to determine the period of free oscillation TA about an axis that is perpendicular to the figure through a point of coordinates A( 202 ,40 ) in mm. The simplest and intuitive splitting of the part in constituting shapes is Area = Area, Areaz with subscript 1 applying to the rectangular part and 2 to the semi-circular one. %3D where h is the distance between point A and the CG. ghArea Calculate the coordinates of the CG in the system of coordinates (z, y). mm thir point onward

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近 A semi-circular piece of radius r= 400 TMm is removed from a rectangular plate of size a = 880 mm,b=480 mm. The thickness is negligible, therefore the rest of the problem can be handled based of areas. Morment of inertia here refers to the second moment of area, dm=[2°&A in m rather than kgm ete EQuiz navigat t of 10 uogsa 21 Finish attempt... Time left 1:57:17 Analyse the part in order to determine the period of free oscillation TA) about an axis that is perpendicular to the figure through a point of coordinates A( 202 , 40 ) in mm. The simplest and intuitive splitting of the part in constituting shapes is Area = Area, – Areaz with subscript 1 applying to the rectangular part and 2 to the semi-circular one. TA) = 2 V ghArea where h is the distance between point A and the CG. Calculate the coordinates of the CG in the system of coordinates (z, y) mm шш Note: You need to be careful with unit and the accuracy of your results from this point onward For the rectangular plate Type here to search
Transcribed Image Text:近 A semi-circular piece of radius r= 400 TMm is removed from a rectangular plate of size a = 880 mm,b=480 mm. The thickness is negligible, therefore the rest of the problem can be handled based of areas. Morment of inertia here refers to the second moment of area, dm=[2°&A in m rather than kgm ete EQuiz navigat t of 10 uogsa 21 Finish attempt... Time left 1:57:17 Analyse the part in order to determine the period of free oscillation TA) about an axis that is perpendicular to the figure through a point of coordinates A( 202 , 40 ) in mm. The simplest and intuitive splitting of the part in constituting shapes is Area = Area, – Areaz with subscript 1 applying to the rectangular part and 2 to the semi-circular one. TA) = 2 V ghArea where h is the distance between point A and the CG. Calculate the coordinates of the CG in the system of coordinates (z, y) mm шш Note: You need to be careful with unit and the accuracy of your results from this point onward For the rectangular plate Type here to search
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