A section of a wing torque box, 40 ft long w/ shear modulus G = 12 x 10^6 psi carries the torque 120 kip.in., has configuration of a semi-circular section w/ radius of 5 in & center at O. (a) Compute the constant thickness t if the shear stress is limited to 12 ksi. (b) Find the constant wall thickness t if the angle of twist is not to exceed 2°. (c) Determine the smallest allowable constant wall thickness t to satisfy both conditions. (Select the three corresponding correct answers) * 0.573 in 0.064 in 0.350 in tmin = 0.350 in tmin = 0.573 in tmin = 0.130 in 0.130 in tmin = 0.064 in

A section of a wing torque box, 40 ft long w/ shear modulus G = 12 x 10^6 psi carries the torque 120 kip.in., has configuration of a semi-circular section w/ radius of 5 in & center at O. (a) Compute the constant thickness t if the shear stress is limited to 12 ksi. (b) Find the constant wall thickness t if the angle of twist is not to exceed 2°. (c) Determine the smallest allowable constant wall thickness t to satisfy both conditions. (Select the three corresponding correct answers) * 0.573 in 0.064 in 0.350 in tmin = 0.350 in tmin = 0.573 in tmin = 0.130 in 0.130 in tmin = 0.064 in

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter8: Applications Of Plane Stress (pressure Vessels, Beams, And Combined Loadings)

Section: Chapter Questions

Problem 8.5.8P: A pressurized cylindrical tank with flat ends is loaded by torques T and tensile forces P (sec...

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Question

A section of a wing torque box, 40 ft long w/ shear modulus G = 12 x 10^6 psi
carries the torque 120 kip.in., has configuration of a semi-circular section w/
radius of 5 in & center at O. (a) Compute the constant thickness t if the shear
stress is limited to 12 ksi. (b) Find the constant wall thickness t if the angle of
twist is not to exceed 2°. (c) Determine the smallest allowable constant wall
thickness t to satisfy both conditions. (Select the three corresponding correct
answers) *
0.573 in
0.064 in
0.350 in
tmin = 0.350 in
tmin = 0.573 in
tmin = 0.130 in
0.130 in
tmin = 0.064 in

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