A scuba diver carries a small balloon of air deep underwater. If the balloon has a volume of 2.11 L at the surface, where the pressure is 102 kPa, what wll the pressure be when the balloon has shrunk to a size of 0.581 L? Assume that the balloon's temperature remains the same throughout its descent.

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A scuba diver carries a small balloon of air deep underwater. If the balloon
has a volume of 2.11 L at the surface, where the pressure is 102 kPa, what will
the pressure be when the balloon has shrunk to a size of 0.581 L? Assume that
the balloon's temperature remains the same throughout its descent.
Transcribed Image Text:A scuba diver carries a small balloon of air deep underwater. If the balloon has a volume of 2.11 L at the surface, where the pressure is 102 kPa, what will the pressure be when the balloon has shrunk to a size of 0.581 L? Assume that the balloon's temperature remains the same throughout its descent.
Expert Solution
Boyle's law

According to Boyle's law, at constant temperature, pressure is inversely related to the volume of a gas. It can be represented as follows:

P~1/V

=> PV = constant    (at constant T) 

 

The relationship for a gas with two different volumes and at two different pressure can be written as follows:

P1 V1 = P2 V2             ••••••(1) 

 

Here, Pis pressure of gas at first condition, Vis volume of gas at first condition, Pis pressure of gas at second condition and Vis volume of gas at second condition. 

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