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A scientist finds that the air trapped in a J tube occupies the volume of 50. 43 cm at 4 bar (initial pressure). By adding mercury into the tube, he increased the pressure of air (His aim is to find the final volume ot air by using R in Latm/(mol. K) in his calculations.) The mathematical operation for the conversion of volume into the desired unit 0.001x50.43 Initial volume after conversion is • Unit b. The mathemantical operation for the conversion of initial pressure into the desired unit 4+L013 Initial pressure is 3.949 Unit atm : Assume that at constant temperature, if initial pressure is 3. 144 atm, final pressure is 21.37 atm and formula to find final volume is

A scientist finds that the air trapped in a J tube occupies the volume of 50. 43 cm at 4 bar (initial pressure). By adding mercury into the tube, he increased the pressure of air (His aim is to find the final volume ot air by using R in Latm/(mol. K) in his calculations.) The mathematical operation for the conversion of volume into the desired unit 0.001x50.43 Initial volume after conversion is • Unit b. The mathemantical operation for the conversion of initial pressure into the desired unit 4+L013 Initial pressure is 3.949 Unit atm : Assume that at constant temperature, if initial pressure is 3. 144 atm, final pressure is 21.37 atm and formula to find final volume is

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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A scientist finds that the air trapped in a J tube occupies the volume of 50. 43 cm at 4 bar (initial pressure). By adding mercury into the tube, he increased the pressure of air (His aim is to find the final volume of air by using R in Latm/(mol. K) in his calculations.) a The mathematical operation for the conversion of volume into the desired unit 0.001x50.43 Initial volume after conversion is • Unit The mathematical operation for the conversion of initial pressure into the desired unit 4+L013 Initial pressure is 3.949 Unit atm : Assume that at constant temperature, if initial pressure is 3. 144 atm, final pressure is 21. 37 atm and formula to find final volume is doubled was reduced to half quadrupled stayed name tripled 5.002 Unit L : during the process
Transcribed Image Text:A scientist finds that the air trapped in a J tube occupies the volume of 50. 43 cm at 4 bar (initial pressure). By adding mercury into the tube, he increased the pressure of air (His aim is to find the final volume of air by using R in Latm/(mol. K) in his calculations.) a The mathematical operation for the conversion of volume into the desired unit 0.001x50.43 Initial volume after conversion is • Unit The mathematical operation for the conversion of initial pressure into the desired unit 4+L013 Initial pressure is 3.949 Unit atm : Assume that at constant temperature, if initial pressure is 3. 144 atm, final pressure is 21. 37 atm and formula to find final volume is doubled was reduced to half quadrupled stayed name tripled 5.002 Unit L : during the process
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