A satellite used in a cellular telephone network has a mass of 2410 kg and is in a circular orbit at a height of 790 km above the surface of the earth. Part A What is the gravitational force Feray on the satellite? Take the gravitational constant to be G = 6.67×10-11 N. m² /kg? , the mass of the earth to be me = 5.97×1024 kg , and the radius of the Earth to be re = 6.38×106 m. %3D %3D Express your answer in newtons. • View Available Hint(s) Fgrav 1.87x104 N %3D Submit Previous Answers

A satellite used in a cellular telephone network has a mass of 2410 kg and is in a circular orbit at a height of 790 km above the surface of the earth. Part A What is the gravitational force Feray on the satellite? Take the gravitational constant to be G = 6.67×10-11 N. m² /kg? , the mass of the earth to be me = 5.97×1024 kg , and the radius of the Earth to be re = 6.38×106 m. %3D %3D Express your answer in newtons. • View Available Hint(s) Fgrav 1.87x104 N %3D Submit Previous Answers

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

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Problem 05, part B

A satellite used in a cellular telephone network has a
mass of 2410 kg and is in a circular orbit at a height of
790 km above the surface of the earth.
Part A
What is the gravitational force Ferav on the satellite?
Take the gravitational constant to be G = 6.67×10-11
N. m2 /kg? , the mass of the earth to be me =
5.97x1024 kg , and the radius of the Earth to be re =
6.38×106 m .
%3D
Express your answer in newtons.
• View Available Hint(s)
Fgrav = 1.87x104 N
%3D
Submit
Previous Answers
Correct
Correct answer is shown. Your answer
18667.2 N was either rounded differently or
used a different number of significant figures
than required for this part.

Part B
What fraction is this of the satellite's weight at the
surface of the earth?
Take the free-fall acceleration at the surface of the
earth to be g = 9.80 m/s?
· View Available Hint(s)
ΑΣφ
?

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