A satellite circles the earth in an orbit whose radius is 2.23 times the earth's radius. The earth's mass is 5.98 x 1024 kg, and its radius is 6.38 x 106 m. What is the period of the satellite?
A satellite circles the earth in an orbit whose radius is 2.23 times the earth's radius. The earth's mass is 5.98 x 1024 kg, and its radius is 6.38 x 106 m. What is the period of the satellite?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Chapter 05, Problem 36
---
#### Your answer is partially correct. Try again.
A satellite circles the earth in an orbit whose radius is 2.23 times the earth's radius. The earth's mass is \( 5.98 \times 10^{24} \) kg, and its radius is \( 6.38 \times 10^{6} \) m. What is the period of the satellite?
---
**Number:** 18031 ☒
**Units:** ✓ S
*The tolerance is +/-2%*
---
### Detailed Explanation of the Given Elements
- The problem contains a calculation related to satellite motion in orbital mechanics.
- The Earth’s mass (\( 5.98 \times 10^{24} \) kg) and radius (\( 6.38 \times 10^{6} \) m) are given.
- The radius of the satellite's orbit is 2.23 times that of the Earth's radius.
- A partially correct answer was provided: 18031 seconds.
This question involves the calculation of the orbital period of the satellite using the given parameters and standard gravitational equations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbc783430-bf94-4e65-bed2-17698c45aa9d%2F58c98872-e6e3-45e5-b961-4524a41e9fa8%2Fjqp6ffa_processed.png&w=3840&q=75)
Transcribed Image Text:### Chapter 05, Problem 36
---
#### Your answer is partially correct. Try again.
A satellite circles the earth in an orbit whose radius is 2.23 times the earth's radius. The earth's mass is \( 5.98 \times 10^{24} \) kg, and its radius is \( 6.38 \times 10^{6} \) m. What is the period of the satellite?
---
**Number:** 18031 ☒
**Units:** ✓ S
*The tolerance is +/-2%*
---
### Detailed Explanation of the Given Elements
- The problem contains a calculation related to satellite motion in orbital mechanics.
- The Earth’s mass (\( 5.98 \times 10^{24} \) kg) and radius (\( 6.38 \times 10^{6} \) m) are given.
- The radius of the satellite's orbit is 2.23 times that of the Earth's radius.
- A partially correct answer was provided: 18031 seconds.
This question involves the calculation of the orbital period of the satellite using the given parameters and standard gravitational equations.
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