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A sample of solid aluminum is heated with an electrical coil. If 157 Joules of energy are added to a 12.9 gram sample initially at 24.3°C, what is the final temperature of the aluminum? Answer: °C.

A sample of solid aluminum is heated with an electrical coil. If 157 Joules of energy are added to a 12.9 gram sample initially at 24.3°C, what is the final temperature of the aluminum? Answer: °C.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Problem Statement:** A sample of **solid aluminum** is heated with an electrical coil. If **157 Joules** of energy are added to a **12.9 gram** sample initially at **24.3°C**, what is the final temperature of the **aluminum**? **Answer:** [ ] °C **Explanation:** To solve this problem, you would typically use the formula for heat transfer: \[ q = mc\Delta T \] Where: - \( q \) is the heat energy (in Joules) - \( m \) is the mass (in grams) - \( c \) is the specific heat capacity (for aluminum, it is approximately \( 0.897 \, \text{J/g°C} \)) - \( \Delta T \) is the change in temperature (in °C) Rearranging the formula to solve for the final temperature gives: \[ \Delta T = \frac{q}{mc} \] Then add the initial temperature to find the final temperature. Plug in the known values to calculate.
Transcribed Image Text:**Problem Statement:** A sample of **solid aluminum** is heated with an electrical coil. If **157 Joules** of energy are added to a **12.9 gram** sample initially at **24.3°C**, what is the final temperature of the **aluminum**? **Answer:** [ ] °C **Explanation:** To solve this problem, you would typically use the formula for heat transfer: \[ q = mc\Delta T \] Where: - \( q \) is the heat energy (in Joules) - \( m \) is the mass (in grams) - \( c \) is the specific heat capacity (for aluminum, it is approximately \( 0.897 \, \text{J/g°C} \)) - \( \Delta T \) is the change in temperature (in °C) Rearranging the formula to solve for the final temperature gives: \[ \Delta T = \frac{q}{mc} \] Then add the initial temperature to find the final temperature. Plug in the known values to calculate.
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