A sample of soil in natural state having volume of 0.00934 cu.m weighs 18.11kg. The sample is allowed to dry in an oven and weight was reduced to 15.67 kg. The specific gravity of solid was found to be 2.67. Determine the following: (a.) Moist unit weight of soil and dry unit weight of soil (b.) Void ratio and porosity (c.) Moisture content and Degree of saturation

A sample of soil in natural state having volume of 0.00934 cu.m weighs 18.11kg. The sample is allowed to dry in an oven and weight was reduced to 15.67 kg. The specific gravity of solid was found to be 2.67. Determine the following: (a.) Moist unit weight of soil and dry unit weight of soil (b.) Void ratio and porosity (c.) Moisture content and Degree of saturation

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A sample of clay soil of volume 1x10^-3 m^3 and mass 1.762 kg, after being dried out in an oven had a mass of 1.368 kg. The specific gravity of the particles was 2.69. a. Compute the void ratio. b. Find the volume of air in the original sample. c. Determine the density of sample of soil when completely saturated, assuming that it has the same void ratio.
The saturated clay sample was weighed in a container and the total weight was 7.4 N. 24 hours 105 degreesAfter waiting in the oven, the container was weighed again, this time it was measured as 5.6 N. The weight of the container is given as 0.7 N. Given the specific gravity of 2.66 for the soil, a) water content b) void ratio c) porosity d) density and e)Calculate the unit weight.
A cylindrical soil sample prepared for laboratory testing has a diameter of 71 mm, a height of 142 mm, and weighs 10.675 x 10-3 kN. If the degree of saturation is 93% and the specific gravity of soil solids is 2.71, determine: void ratio water content water content under fully saturated condition
a soil sample was determined to have a water content of 8% and a degree of saturation of 42%. After adding some water, the degree of saturation was altered to 53%. take the specific gravity of the soil solids to be 2.7. assuming no change in the volume of the voids, determine the following A. void ratio B. water content% C. bulk specific gravity of the mass of the sample in the altered state.
The moist unit weights and degrees of saturation of a soil sample are given as follows: a. Determine the specific gravity of the soil solidsb. Determine the porosity.c. Find the dry unit weight of soil
3. A soil sample has a a volume of 0.4 m³. The moist soil has a mass of 711.2 kg. When it is dried out in the oven, it is mass was 623.9 kg. The specific gravity of the solids is 2.68. Find the following: (a) water content (b) void ratio (c) degree of saturation (d) bulk (moist) density (kg/m³). (e) dry density (kg/m³). (f) saturated density (kg/m³). (g) moist unit weight (kN/m³) (h) dry unit weight (kN/m³) (i) saturated unit weight (kN/m³) Solve the problem using the phase diagram (Check parts (d) to (f) using the equations)
(detailed and clean solution please) large soil sample obtained from a borrow pit has a wet mass of 26.50kg. the in – place volume occupied by the sample is 0.013m3. A small portion of the sample is used to determine the water content; the wet mass is 135g, and after drying in an oven, the mass is 117g. a. Determine the soil’s water content. b. Determine the soil wet and dry density for conditions at the borrow pit.
It is needed to determine the moist unit weight of the soil for field compaction testing. A silty soil sample has a mass of 612 grams. The soil sample was then covered in beeswax and the combined weight was 650 g. The soil covered in wax, was then immersed in the water and the graduated cylinder registered a volume difference of 404 ml. The wax was gently peeled off the soil. Moisture content = 12% Specific Gravity = 2.78 But if the wax has a specific gravity of 0.94, determine the following: Dry unit weight of the soil Void ratio of the soil % of air in relation to the soil solids of the sample
A soil sample is oven-dried from its liquid limit state to its dry state causing a volume change of 60% of the dry volume. Likewise, the same soil is oven-dried from its plastic limit state to its dry state causing a volume change of 20% of the dry volume. The liquid limit and plastic limit are 54% and 26%, respectively. Determine the specific gravity of soil solids, shrinkage limit and shrinkage ratio. 1. INPUT THE VALUE OF SPECIFIC GRAVITY OF SOIL SOLIDS IN 2 DECIMAL PLACES 2. INPUT THE VALUE OF SHRINKAGE LIMIT IN PERCENTAGE FORM AND IN 2 DECIMAL PLACES 3. INPUT THE VALUE OF SHRINKAGE RATIO IN 2 DECIMAL PLACES Answer with text and/or attachments:
A soils specimen has a total volume of 95000 mm3 and its mass is 175 g. The dry mass of the specimen is 167 g, and the density of the soil solids is 2.70 Mg/m3. Find: water content, void ratio, porosity, degree of saturation, wet density, dry density. Give the wet and dry density in both SI and British units.
A sample of soil has a volume of 0.57 ft³ and a weight of 57.30 lb. After being dried in an oven, it has a weight of 49.10 lb. It has a specific gravity of solids of 2.66. Compute its moisture content and degree of saturation before it was placed in the oven. Solution: ● ● ● Moisture content: @ = Unit weight of water is: %d Degree of saturation: S = = %; lb/ft³; %.
05: The Figure below represents the data that was obtained from a liquid-limit test on a soil. 50 percent of its particles is passing sieve #200. Two determinations for the plastic limit gave water contents of 20.3 % and 20.8 %. Determine 1- Liquid Limit (LL). 2- Plasticity index. 3- Liquidity index if the water content is 27.4% 4- Void ratio at the liquid limit, if G, 2.7 5- Classify the soil based on AASHTO system. 30 10 20 40 60 80 100 Penetration, d (mm) Moisture content, w ()